java 方法返回值 和调用方法的对象

[agbbbb]

新人正在学正则表达式，看的马士兵老师的视频，学习过程中看到这么一串代码：
Pattern p = Pattern.compile("\\d{3,5}");
String s = "123-34345-234-00";
Matcher m = p.matcher(s);
print(m.find());

上面调用的print()方法：
public static void print(Object o ){
System.out.println(o);
}

上面那段代码里：
第一句，生成一个正则表达式模板，是不是这句执行完了以后，变量p = "\\d{3,5}?
如果是的话，那Pattern型变量也是正则表达式（字符串）？
第三句，p.matcher(s); 这句是把p变成m，还是把穿进去的参数s变成m？
第四句，m.find();找匹配，找m与谁匹配的啊，还是上面这几个语句用的时候是放在一起用的？那才能看出是跟谁匹配？
求高手有时间帮忙回复下，谢谢

[李德胜1995]

自己看jdk文档。。。。

[markfengfeng]

或许Pattern类的注释可以解答： /** * A compiled representation of a regular expression. * * <p> A regular expression, specified as a string, must first be compiled into * an instance of this class. The resulting pattern can then be used to create * a {@link Matcher} object that can match arbitrary {@linkplain * java.lang.CharSequence character sequences} against the regular * expression. All of the state involved in performing a match resides in the * matcher, so many matchers can share the same pattern. * * <p> A typical invocation sequence is thus * * <blockquote><pre> * Pattern p = Pattern.{@link #compile compile}("a*b"); * Matcher m = p.{@link #matcher matcher}("aaaaab"); * boolean b = m.{@link Matcher#matches matches}();</pre></blockquote> * * <p> A {@link #matches matches} method is defined by this class as a * convenience for when a regular expression is used just once. This method * compiles an expression and matches an input sequence against it in a single * invocation. The statement * * <blockquote><pre> * boolean b = Pattern.matches("a*b", "aaaaab");</pre></blockquote> * * is equivalent to the three statements above, though for repeated matches it * is less efficient since it does not allow the compiled pattern to be reused. * * <p> Instances of this class are immutable and are safe for use by multiple * concurrent threads. Instances of the {@link Matcher} class are not safe for * such use. 我英语也二把刀，但是借助翻译软件还是能看懂的。你自己琢磨琢磨。

[maradona1984]

问号太多,你到底想知道什么?

[自由自在_Yu]

你把每一个都打印出来就知道啦，，，，，，