json格式转换问题，怎么搞，谢谢各位

[nitaiyoucala]

{"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试"}
转换成
[{"TT":"abac","BB":"电工电子产品"},{"TT":"xxxxxx","BB":"测试"}]

[文盲老顾]

	var t = {"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试",'TT2':'yyyy','BB2':'test'}
	var tt = [{}];
	for(var i in t){
		var exists = false
		for (var j in tt[0])
		{
			if (new RegExp('^'+j+'\\d+$','g').test(i))
			{
				if (!tt[parseInt(i.replace(new RegExp('^'+j,'g'),''))])
				{
					tt[parseInt(i.replace(new RegExp('^'+j,'g'),''))]={}
				}
				tt[parseInt(i.replace(new RegExp('^'+j,'g'),''))][j]=t[i];
				exists = true;
			}
		}
		if (!exists)
		{
			tt[0][i] = t[i];
		}
	}
	console.log(tt)

[scscms太阳光]

常常谈代码要健壮要健壮，如何健壮？就是同一个需求中，你的代码尽可能适应数据的改变，而不需要改动你的代码！

    var obj = {"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试",'wx':'键名不可控',wx1:'键名不可控1'};
    var arr = [];
    JSON.stringify(obj).replace(/"([a-z]+)(\d+)?":"(.*?)"/ig, function (s, k, i, v) {
        i = i ? i : 0;
        (arr[i]||(arr[i] = {}))[k] = v;
    });
    console.log(arr);

[apple8160]

var j={"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试"};
var j1=[];
j1.push(j);

[Go 旅城通票]

    var d = { "TT": "abac", "BB": "电工电子产品", "TT1": "xxxxxx", "BB1": "测试" }
    var nd = []
    for (i = 0; i < 100; i++) {
        if (d['TT' + (i ? i : '')]) nd.push({ TT: d['TT' + (i ? i : '')], BB: d['BB' + (i ? i : '')]||'' });
    }
    console.log(nd)

Web开发学习资料推荐
jqGrid行编辑配置
jQuery仿excel表格单元格合并插件

[functionsub]

var obj = {"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试"};
var reg = /(?:TT|BB)(\d*)/;
var res = [];
var temp = {};
for(var p in obj){
    var match = p.match(reg);
    if(match){
        var num = match[1];
        var tempKey = 'TT'+num + 'BB' + num;
        if(!temp[tempKey]){
            temp[tempKey] = {};
        }
        temp[tempKey][match[0]] = obj[p];
    }
}
for(var p in temp){
    res.push(temp[p]);
}

[functionsub]

var obj = {"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试"};
var reg = /(TT|BB)(\d*)/;
var res = [];
var temp = {};
for(var p in obj){
    var match = p.match(reg);
    if(match){
        var num = match[2];
        var tempKey = 'TT'+num + 'BB' + num;
        if(!temp[tempKey]){
            temp[tempKey] = {};
        }
        temp[tempKey][match[1]] = obj[p];
    }
}
for(var p in temp){
    res.push(temp[p]);
}

emmmm，上面忘记把属性名后面点数字去掉了。要加字段的话就在reg第一个括号里加。 比如以后还要加一个CC那就改成

var reg = /(TT|BB|CC)(\d*)/;

[jio可]

都知道属性名为什么不直接写

var obj = {"TT":"abac","BB":"电工电子产品","TT1":"xxxxxx","BB1":"测试"}; var arr = [{TT:obj.TT,BB:obj.BB},{TT:obj.TT1,BB:obj.BB1}];