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分享基于C#调用的百度地图如何把地图上两点按照马路走向相连？
具体的就是通过收到两个经纬度信息，在地图上定位两点，将这两点像导航里那样连接。
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threenewbee 2018-02-02
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http://download.csdn.net/download/u011486249/8347231
zmyouren1983 2018-02-02
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1、首先用一个html文件调用百度地图接口（主要注册一个序列号）：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>百度地图的Hello World</title>
<style type="text/css">
body, html, #allmap
{
width: 100%;
height: 100%;
overflow: hidden;
margin: 0;
}
#l-map
{
height: 100%;
width: 78%;
float: left;
border-right: 2px solid #bcbcbc;
}
#r-result
{
height: 100%;
width: 20%;
float: left;
}
</style>
<script type="text/javascript" src="http://api.map.baidu.com/api?v=1.5&ak=6c497f51c06477544e5fa6e9bd68f7c3"></script>
</head>
<body>
<div id="allmap">
</div>
</body>
</html>
<script type="text/javascript">
// 百度地图API功能
var map = new BMap.Map("allmap");
map.centerAndZoom(new BMap.Point(116.404, 39.915), 15);
function setdriving(x,y,z,w){
var myP1 = new BMap.Point(x,y); //起点
var myP2 = new BMap.Point(z,y); //终点
var driving2 = new BMap.DrivingRoute(map, {renderOptions:{map: map, autoViewport: true}});
driving2.search(myP1, myP2);
}
</script> using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
try
{
webBrowser1.Url = new Uri("http://127.0.0.1/route.html");
}
catch (Exception ex)
{
MessageBox.Show(ex.Message, "异常", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
}
private void webBrowser1_DocumentCompleted(object sender, WebBrowserDocumentCompletedEventArgs e)
{
webBrowser1.Document.InvokeScript("setdriving", new object[] { 116.380967, 39.913285, 116.424374, 39.914668 });
}
}
}
