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static void Main(string[] args)
{
Console.WriteLine(new Regex("aaa").Replace("aaa0009978796aaa", "", 1));
Console.WriteLine(Regex.Replace("aaa0009978796aaa", "^aaa", ""));
Console.WriteLine(Regex.Replace("aaa0009978796aaa", "aaa(?!$)", ""));
}
string result = Regex.Replace(input, @"([a-zA-Z]+)(\d+)", "$2");
new Regex("").Replace("", "", 1)
三个空字符串自行查看方法注释