正则 取固定首尾

[FarbeTnT]

例如<!log>111111111111111111111111111111111111111<?log>
<!log>22222222222222222222222222<?log>
怎么能获取<!log><?log>中间的部分，包括换行。。。

[FarbeTnT]

引用 2 楼 oyljerry 的回复:

String log = "<!log>111111111111111111111111111111111111111<?log>";
        Pattern log_ptn = Pattern.compile("<!log>([\\s\\S]+)<\\?log>");
        Matcher log_m = log_ptn.matcher(log);
        while (log_m.find()) {
            System.out.println("log = " + log_m.group(1));
        }

遇到换行好像不行啊老哥

[hbhbhbhbhb1021]

可以的啊，举个不行的例子呢？

[Braska]

Matcher matcher = Pattern.compile("(?<=(<!log>))[\\w\\W]*(?=(<\\?log>))")
                .matcher("<!log>22222222222\n222222222222222<?log>");
        
        while(matcher.find()) {
            System.out.println(matcher.group(0));
        }

[oyljerry]

String log = "<!log>111111111111111111111111111111111111111<?log>";
        Pattern log_ptn = Pattern.compile("<!log>([\\s\\S]+)<\\?log>");
        Matcher log_m = log_ptn.matcher(log);
        while (log_m.find()) {
            System.out.println("log = " + log_m.group(1));
        }