用dom4j解析xml格式的字符串时报错[Document: name null] 找不到下面的节点

[selina_vip]

示例代码如下：

String respXmlData = "<RespInfo><ResultStatus>02</ResultStatus><ResultCode>BD1003</ResultCode></RespInfo>";
try {
	Document document = DocumentHelper.parseText(respXmlData);
	System.out.println(document.asXML().toString());
	// 获取节点元素对象与值
	Element rootNode = document.getRootElement();
	Element respInfoNode = rootNode.element("RespInfo");
	System.out.println(respInfoNode.getText());
} catch (DocumentException e) {
	e.printStackTrace();
}

获取rootNode这些都是为空，请各位大神帮忙看看

[QWERT4745]

document.getRootElement()已经获取到的根节点下的元素，也就是<ResultStatus>02</ResultStatus><ResultCode>BD1003</ResultCode>，不能再去取RespInfo，而要改成

Document document = DocumentHelper.parseText(respXmlData);
System.out.println(document.asXML().toString());
// 获取节点元素对象与值
Element rootNode = document.getRootElement();
Element resultStatus = rootNode.element("ResultStatus");
Element resultCode = rootNode.element("ResultCode");
System.out.println(resultStatus.getText());
System.out.println(resultCode.getText());

[selina_vip]

后面才明白节点需要层层获取

String respXmlData = "<?xml version=\"1.0\" encoding=\"UTF-8\" ?><Document><RespInfo><ResultStatus>02</ResultStatus><ResultCode>BD1003</ResultCode></RespInfo></Document>";
try {
	Document document = DocumentHelper.parseText(respXmlData);
	System.out.println(document.asXML().toString());
	// 获取节点元素对象与值
	Element rootNode = document.getRootElement();
	System.out.println("根节点名称是：" + rootNode.getName());
	Element respInfoNode = rootNode.element("RespInfo");
	System.out.println(respInfoNode.element("ResultStatus").getText());
} catch (DocumentException e) {
	e.printStackTrace();
}