统计两次评分相同的个数

[伟洪winni]

$list = [
            ['score1' => 'A', 'score2' => 'C'],
            ['score1' => 'D', 'score2' => 'B'],
            ['score1' => 'B', 'score2' => 'B'],
            ['score1' => 'A', 'score2' => 'B'],
            ['score1' => 'C', 'score2' => 'C'],
            ['score1' => 'B', 'score2' => 'D'],
            ['score1' => 'B', 'score2' => 'B'],
            ['score1' => 'A', 'score2' => 'B'],
            ['score1' => 'A', 'score2' => 'A'],
            ['score1' => 'D', 'score2' => 'D'],
        ];

怎么统计score1和score2相同的个数? (循环if ++ 的方案除外)

[qq_36802756]

foreach ($list as $key => $value) { if ($value['score1']!=$value['score2']) { unset($list[$key]); } }

[ayzen1988]

$newlist = array_filter($list, function($itm) {
    return $itm['score1'] == $itm['score2'];
});
var_dump(count($newlist));

[xuzuning]

$list = [
            ['score1' => 'A', 'score2' => 'C'],
            ['score1' => 'D', 'score2' => 'B'],
            ['score1' => 'B', 'score2' => 'B'],
            ['score1' => 'A', 'score2' => 'B'],
            ['score1' => 'C', 'score2' => 'C'],
            ['score1' => 'B', 'score2' => 'D'],
            ['score1' => 'B', 'score2' => 'B'],
            ['score1' => 'A', 'score2' => 'B'],
            ['score1' => 'A', 'score2' => 'A'],
            ['score1' => 'D', 'score2' => 'D'],
        ];
foreach($list as $v) {
  $a[] = $v['score1'];
  $b[] = $v['score2'];
}
print_r(array_intersect_assoc($a,$b));

Array
(
    [2] => B
    [4] => C
    [6] => B
    [8] => A
    [9] => D
)

[一生小白]

用array_search