-
本版专家分：0结帖率 100% -
var o, p, q, r, s, t, u, v, w, x = [], y = 7, z = 12, A = 17, B = 22, C = 5, D = 9, E = 14, F = 20, G = 4, H = 11, I = 16, J = 23, K = 6, L = 10, M = 15, N = 21;
for (a = n(a),
x = l(a),
t = 1732584193,
u = 4023233417,
v = 2562383102,
w = 271733878,
o = 0; o < x.length; o += 16)
p = t,
q = u,
r = v,
s = w,
t = h(t, u, v, w, x[o + 0], y, 3614090360),
w = h(w, t, u, v, x[o + 1], z, 3905402710),
v = h(v, w, t, u, x[o + 2], A, 606105819),
u = h(u, v, w, t, x[o + 3], B, 3250441966),
t = h(t, u, v, w, x[o + 4], y, 4118548399),
w = h(w, t, u, v, x[o + 5], z, 1200080426),
v = h(v, w, t, u, x[o + 6], A, 2821735955),
u = h(u, v, w, t, x[o + 7], B, 4249261313),
t = h(t, u, v, w, x[o + 8], y, 1770035416),
w = h(w, t, u, v, x[o + 9], z, 2336552879),
v = h(v, w, t, u, x[o + 10], A, 4294925233),
u = h(u, v, w, t, x[o + 11], B, 2304563134),
t = h(t, u, v, w, x[o + 12], y, 1804603682),
w = h(w, t, u, v, x[o + 13], z, 4254626195),
v = h(v, w, t, u, x[o + 14], A, 2792965006),
u = h(u, v, w, t, x[o + 15], B, 1236535329),
t = i(t, u, v, w, x[o + 1], C, 4129170786),
w = i(w, t, u, v, x[o + 6], D, 3225465664),
v = i(v, w, t, u, x[o + 11], E, 643717713),
u = i(u, v, w, t, x[o + 0], F, 3921069994),
t = i(t, u, v, w, x[o + 5], C, 3593408605),
w = i(w, t, u, v, x[o + 10], D, 38016083),
v = i(v, w, t, u, x[o + 15], E, 3634488961),
u = i(u, v, w, t, x[o + 4], F, 3889429448),
t = i(t, u, v, w, x[o + 9], C, 568446438),
w = i(w, t, u, v, x[o + 14], D, 3275163606),
v = i(v, w, t, u, x[o + 3], E, 4107603335),
u = i(u, v, w, t, x[o + 8], F, 1163531501),
t = i(t, u, v, w, x[o + 13], C, 2850285829),
w = i(w, t, u, v, x[o + 2], D, 4243563512),
v = i(v, w, t, u, x[o + 7], E, 1735328473),
u = i(u, v, w, t, x[o + 12], F, 2368359562),
t = j(t, u, v, w, x[o + 5], G, 4294588738),
w = j(w, t, u, v, x[o + 8], H, 2272392833),
v = j(v, w, t, u, x[o + 11], I, 1839030562),
u = j(u, v, w, t, x[o + 14], J, 4259657740),
t = j(t, u, v, w, x[o + 1], G, 2763975236),
w = j(w, t, u, v, x[o + 4], H, 1272893353),
v = j(v, w, t, u, x[o + 7], I, 4139469664),
u = j(u, v, w, t, x[o + 10], J, 3200236656),
t = j(t, u, v, w, x[o + 13], G, 681279174),
w = j(w, t, u, v, x[o + 0], H, 3936430074),
v = j(v, w, t, u, x[o + 3], I, 3572445317),
u = j(u, v, w, t, x[o + 6], J, 76029189),
t = j(t, u, v, w, x[o + 9], G, 3654602809),
w = j(w, t, u, v, x[o + 12], H, 3873151461),
v = j(v, w, t, u, x[o + 15], I, 530742520),
u = j(u, v, w, t, x[o + 2], J, 3299628645),
t = k(t, u, v, w, x[o + 0], K, 4096336452),
w = k(w, t, u, v, x[o + 7], L, 1126891415),
v = k(v, w, t, u, x[o + 14], M, 2878612391),
u = k(u, v, w, t, x[o + 5], N, 4237533241),
t = k(t, u, v, w, x[o + 12], K, 1700485571),
w = k(w, t, u, v, x[o + 3], L, 2399980690),
v = k(v, w, t, u, x[o + 10], M, 4293915773),
u = k(u, v, w, t, x[o + 1], N, 2240044497),
t = k(t, u, v, w, x[o + 8], K, 1873313359),
w = k(w, t, u, v, x[o + 15], L, 4264355552),
v = k(v, w, t, u, x[o + 6], M, 2734768916),
u = k(u, v, w, t, x[o + 13], N, 1309151649),
t = k(t, u, v, w, x[o + 4], K, 4149444226),
w = k(w, t, u, v, x[o + 11], L, 3174756917),
v = k(v, w, t, u, x[o + 2], M, 718787259),
u = k(u, v, w, t, x[o + 9], N, 3951481745),
t = c(t, p),
u = c(u, q),
v = c(v, r),
w = c(w, s);
var O = m(t) + m(u) + m(v) + m(w);
return O.toLowerCase()
}问题点数：50分
-
本版专家分：69
-
看起来像是MD5的算法
-
本版专家分：69
-
function binlMD5 (x, len) {
/* append padding */
x[len >> 5] |= 0x80 << (len % 32)
x[((len + 64) >>> 9 << 4) + 14] = len
var i
var olda
var oldb
var oldc
var oldd
var a = 1732584193
var b = -271733879
var c = -1732584194
var d = 271733878
for (i = 0; i < x.length; i += 16) {
olda = a
oldb = b
oldc = c
oldd = d
a = md5ff(a, b, c, d, x[i], 7, -680876936)
d = md5ff(d, a, b, c, x[i + 1], 12, -389564586)
c = md5ff(c, d, a, b, x[i + 2], 17, 606105819)
b = md5ff(b, c, d, a, x[i + 3], 22, -1044525330)
a = md5ff(a, b, c, d, x[i + 4], 7, -176418897)
d = md5ff(d, a, b, c, x[i + 5], 12, 1200080426)
c = md5ff(c, d, a, b, x[i + 6], 17, -1473231341)
b = md5ff(b, c, d, a, x[i + 7], 22, -45705983)
a = md5ff(a, b, c, d, x[i + 8], 7, 1770035416)
d = md5ff(d, a, b, c, x[i + 9], 12, -1958414417)
c = md5ff(c, d, a, b, x[i + 10], 17, -42063)
b = md5ff(b, c, d, a, x[i + 11], 22, -1990404162)
a = md5ff(a, b, c, d, x[i + 12], 7, 1804603682)
d = md5ff(d, a, b, c, x[i + 13], 12, -40341101)
c = md5ff(c, d, a, b, x[i + 14], 17, -1502002290)
b = md5ff(b, c, d, a, x[i + 15], 22, 1236535329)
a = md5gg(a, b, c, d, x[i + 1], 5, -165796510)
d = md5gg(d, a, b, c, x[i + 6], 9, -1069501632)
c = md5gg(c, d, a, b, x[i + 11], 14, 643717713)
b = md5gg(b, c, d, a, x[i], 20, -373897302)
a = md5gg(a, b, c, d, x[i + 5], 5, -701558691)
d = md5gg(d, a, b, c, x[i + 10], 9, 38016083)
c = md5gg(c, d, a, b, x[i + 15], 14, -660478335)
b = md5gg(b, c, d, a, x[i + 4], 20, -405537848)
a = md5gg(a, b, c, d, x[i + 9], 5, 568446438)
d = md5gg(d, a, b, c, x[i + 14], 9, -1019803690)
c = md5gg(c, d, a, b, x[i + 3], 14, -187363961)
b = md5gg(b, c, d, a, x[i + 8], 20, 1163531501)
a = md5gg(a, b, c, d, x[i + 13], 5, -1444681467)
d = md5gg(d, a, b, c, x[i + 2], 9, -51403784)
c = md5gg(c, d, a, b, x[i + 7], 14, 1735328473)
b = md5gg(b, c, d, a, x[i + 12], 20, -1926607734)
a = md5hh(a, b, c, d, x[i + 5], 4, -378558)
d = md5hh(d, a, b, c, x[i + 8], 11, -2022574463)
c = md5hh(c, d, a, b, x[i + 11], 16, 1839030562)
b = md5hh(b, c, d, a, x[i + 14], 23, -35309556)
a = md5hh(a, b, c, d, x[i + 1], 4, -1530992060)
d = md5hh(d, a, b, c, x[i + 4], 11, 1272893353)
c = md5hh(c, d, a, b, x[i + 7], 16, -155497632)
b = md5hh(b, c, d, a, x[i + 10], 23, -1094730640)
a = md5hh(a, b, c, d, x[i + 13], 4, 681279174)
d = md5hh(d, a, b, c, x[i], 11, -358537222)
c = md5hh(c, d, a, b, x[i + 3], 16, -722521979)
b = md5hh(b, c, d, a, x[i + 6], 23, 76029189)
a = md5hh(a, b, c, d, x[i + 9], 4, -640364487)
d = md5hh(d, a, b, c, x[i + 12], 11, -421815835)
c = md5hh(c, d, a, b, x[i + 15], 16, 530742520)
b = md5hh(b, c, d, a, x[i + 2], 23, -995338651)
a = md5ii(a, b, c, d, x[i], 6, -198630844)
d = md5ii(d, a, b, c, x[i + 7], 10, 1126891415)
c = md5ii(c, d, a, b, x[i + 14], 15, -1416354905)
b = md5ii(b, c, d, a, x[i + 5], 21, -57434055)
a = md5ii(a, b, c, d, x[i + 12], 6, 1700485571)
d = md5ii(d, a, b, c, x[i + 3], 10, -1894986606)
c = md5ii(c, d, a, b, x[i + 10], 15, -1051523)
b = md5ii(b, c, d, a, x[i + 1], 21, -2054922799)
a = md5ii(a, b, c, d, x[i + 8], 6, 1873313359)
d = md5ii(d, a, b, c, x[i + 15], 10, -30611744)
c = md5ii(c, d, a, b, x[i + 6], 15, -1560198380)
b = md5ii(b, c, d, a, x[i + 13], 21, 1309151649)
a = md5ii(a, b, c, d, x[i + 4], 6, -145523070)
d = md5ii(d, a, b, c, x[i + 11], 10, -1120210379)
c = md5ii(c, d, a, b, x[i + 2], 15, 718787259)
b = md5ii(b, c, d, a, x[i + 9], 21, -343485551)
a = safeAdd(a, olda)
b = safeAdd(b, oldb)
c = safeAdd(c, oldc)
d = safeAdd(d, oldd)
}
return [a, b, c, d]
}
标准MD5算法，你的可能是改了一些种子数吧
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- char* bstr =rn "ABCDEFGHIJKLMNOPQ"rn "RSTUVWXYZabcdefgh"rn "ijklmnopqrstuvwxy"rn "z0123456789+/";rnrnchar rstr[] = rn 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, rn 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, rn 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 62, 0, 0, 0, 63, rn 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 0, 0, 0, 0, 0, 0, rn 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, rn 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 0, 0, 0, 0, 0, rn 0, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, rn 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 0, 0, 0, 0, 0;rnrnrnvoid encode(const char* input,size_t l,string& output, bool add_crlf)rnrn size_t i = 0;rn size_t o = 0;rn rn output = "";rn while (i < l)rn rn size_t remain = l - i;rn if (add_crlf && o && o % 76 == 0)rn output += "\n";rn switch (remain)rn rn case 1:rn output += bstr[ ((input[i] >> 2) & 0x3f) ];rn output += bstr[ ((input[i] << 4) & 0x30) ];rn output += "==";rn break;rn case 2:rn output += bstr[ ((input[i] >> 2) & 0x3f) ];rn output += bstr[ ((input[i] << 4) & 0x30) + ((input[i + 1] >> 4) & 0x0f) ];rn output += bstr[ ((input[i + 1] << 2) & 0x3c) ];rn output += "=";rn break;rn default:rn output += bstr[ ((input[i] >> 2) & 0x3f) ];rn output += bstr[ ((input[i] << 4) & 0x30) + ((input[i + 1] >> 4) & 0x0f) ];rn output += bstr[ ((input[i + 1] << 2) & 0x3c) + ((input[i + 2] >> 6) & 0x03) ];rn output += bstr[ (input[i + 2] & 0x3f) ];rn rn o += 4;rn i += 3;rn rnrnrnvoid decode(const std::string& input,std::string& output)rnrn size_t i = 0;rn size_t l = input.size();rn rn output = "";rn while (i < l)rn rn while (i < l && (input[i] == 13 || input[i] == 10))rn i++;rn if (i < l)rn rn char b1 = (char)((rstr[(int)input[i]] << 2 & 0xfc) +rn (rstr[(int)input[i + 1]] >> 4 & 0x03));rn output += b1;rn if (input[i + 2] != '=')rn rn char b2 = (char)((rstr[(int)input[i + 1]] << 4 & 0xf0) +rn (rstr[(int)input[i + 2]] >> 2 & 0x0f));rn output += b2;rn rn if (input[i + 3] != '=')rn rn char b3 = (char)((rstr[(int)input[i + 2]] << 6 & 0xc0) +rn rstr[(int)input[i + 3]]);rn output += b3;rn rn i += 4;rn rn rn
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- [code=JScript]rnvar Tween = rn Quart: rn easeOut: function(t,b,c,d)rn return -c * ((t=t/d-1)*t*t*t - 1) + b;rn rn ,rn Back: rn easeOut: function(t,b,c,d,s)rn if (s == undefined) s = 1.70158;rn return c*((t=t/d-1)*t*((s+1)*t + s) + 1) + b;rn rn ,rn Bounce: rn easeOut: function(t,b,c,d)rn if ((t/=d) < (1/2.75)) rn return c*(7.5625*t*t) + b;rn else if (t < (2/2.75)) rn return c*(7.5625*(t-=(1.5/2.75))*t + .75) + b;rn else if (t < (2.5/2.75)) rn return c*(7.5625*(t-=(2.25/2.75))*t + .9375) + b;rn else rn return c*(7.5625*(t-=(2.625/2.75))*t + .984375) + b;rn rn rn rnrn[/code]rnrn这段CODE看得头晕死了，汗，就是不明白什么意思
- js字符串加密的几种方法
- 在做web前端的时候免不了要用javascript来处理一些简单操作，其实如果要用好JQuery, Prototype,Dojo 等其中一两个javascript框架并不简单，它提高你的web交互和用户体验，从而能使你的web前端有非一样的感觉，如海阔凭鱼跃。当然，对于javascript我也是半桶水。高手莫怪，在此我仅总结学习一下，以备用到时查录。 今天不说框架的事情，就从最基本的、比较常用的
- 帮忙看下这段程序
- #include "stdafx.h" rn #include rn rn /*##/*~~~~~~~~~~ Noted by [2002-6-21 10:30:39] ~~~~~~~~~~~*/ rn /* rn /* 乘坐公共汽车时的换车问题。例如从站A到Z要坐几路车，换几次，在哪里换车，这些问题如何解决。 rn /* 车次 车站 rn /* 1 q,w,e,r,t,y rn /* 2 a,s,d,f,g,h rn /* 3 z,x,c,v,b,n rn /* 4 p,o,i,u,y,t rn /* 5 l,k,j,h,g,f rn /* 6 m,n,b,v,c,x rn /* 7 q,a,z,w,s,x rn /* rn /*________________ Ended Note [2002-6-21 10:30:39] _____________________##*/ rn rn #define M 7 // 车次数 rn rn // 车次停靠站列表 rn char *Station[M] = rn "QWERTY", // 第0次车 rn "ASDFGH", // 第1次车 rn "ZXCVBN", // 第2次车 rn "POIUYT", // 第3次车 rn "LKJHGF", // 第4次车 rn "MABVCX", // 第5次车 rn "QAZWSX";// 第6次车 rn rn // 已经乘着过的车次列表，对应take[i]=0表示还未乘着，＝1表示已经乘着过 rn int taked[M]=0; rn rn // 换车的下车点 rn struct Exchange rn rn static int Len; // 长度 rn int route; // 车次 rn char pos; // 换车站点 rn Path[M]; // 换车路径 rn rn int Exchange::Len = 0; // 初始化路径长度 rn rn bool PassBy(char P, char* path) // 看路径path的车是否经过点P rn rn while(*path!='\0') if( P==*(path++) ) return true; rn return false; rn rn rn // 打印路径，没得说 rn void print_path() rn rn static int cnt = 0; rn printf("%04d",++cnt); rn for(int i=0;i ",Path[i].route+1,Path[i].pos); rn printf(" (%2d: %c) ",Path[i].route+1,Path[i].pos); rn printf("\n"); rn rn rn[color=#FF0000]void NextSearchPath(char end,int route) // 递归寻找路径 rn rn if( taked[route]!=0 ) return; // have been taked; rn rn if( PassBy(end,Station[route]) ) rn rn Path[Path[0].Len].pos = end; rn Path[Path[0].Len].route = route; rn Path[0].Len++; rn print_path(); rn Path[0].Len--; rn return; rn rn rntaked[route] = 1; //have been taked; rn Path[Path[0].Len].route = route; rn rn for(int i=0;i
- 帮忙看下这段小代码
- 我想对childNodes属性进行测试，所以写了一个小代码rn welcometohere这是测试的标签rnrn
- 帮忙看下这段代码
- $GLOBALS['_arclistEnv'] = 'index';rn $row = $dsql->GetOne("Select * From `#@__homepageset`");rn $row['templet'] = MfTemplet($row['templet']);rn $pv = new PartView();rn $pv->SetTemplet($cfg_basedir . $cfg_templets_dir . "/" . $row['templet']);rn $pv->SaveToHtml(DEDEROOT.'/index.html');rn这个index.html会放到哪里?
- 帮忙看下这段JS代码
- 这是自定义验证控件的客户端代码rn rn为什么我输入的长度是11还是返回false 哪错了吗？
- 帮忙看下这段代码！
- if(objder.Read())rn rn if(passd==objder.GetValue(2).ToString())rn rn 如果执行了这段代码rn Session["id"]=objder.GetValue(0);rn Response.Redirect(burl);rn rn rn elsern rn error.InnerHtml=" 密码错误！";rn return;rn rnrn rn elsern rn error.InnerHtml=" 错误，用户名不存在！";rn return;rn rn objder.Close();rn objcom.Dispose();rn conn.Close();rnrnrnrnrnrn 如果执行了这段代码rn Session["id"]=objder.GetValue(0);rn Response.Redirect(burl);rnrn底下的代码 objder.Close(); objcom.Dispose(); conn.Close();这些代码还会执行吗？rn
- 帮忙看下这段代码~~
- [url=http://blog.csdn.net/KingWolfOfSky/archive/2009/08/13/4444231.aspx][/url]rn这篇博客里面讲了些关于Java细节方面的内容，它给了下面段代码，对输出还是不理解，麻烦各位大虾给解释下~~rn[code=Java]rn 1. public static void main(String args[]) rn 2. rn 3. Integer i1=new Integer(13); rn 4. Integer i2=new Integer(13); rn 5. int i3=13; rn 6. System.out.println(i1==i2); rn 7. System.out.println(i2==i3); rn 8. System.out.println(i3==i1); rn 9. rn 10. * Output rn 11. * true rn 12. * false rn 13. * true rn 14. */ rn[/code]rnrn还有他说了自动包装时对于从–128到127之间的值，它们被包装为Integer对象后，会存在内存中被重用，而其它的值，被包装后的Integer对象并不会被重用，即相当于每次包装时都新建一个Integer对象。rn这是为什么？rn小弟新人，先谢谢各位了~~
- 帮忙看下这段汇编代码
- 现学现卖,实在是无能为力啊.麻烦各位大牛帮帮忙.[code=c]#include rnrnint spinlock_init(PSPINLOCK plock)rnrn if (NULL == plock)rn rn return RET_FAILED;rn rnrn plock->lock = LOCK_UNLOCKED;rn plock->pid = THREAD_DEFAULT;rnrn return RET_SUCCESS;rnrnrnint spinlock_wait(PSPINLOCK plock)rnrn int ret = RET_SUCCESS;rn lock_t lock = LOCK_LOCKED;rn lock_t unlock = LOCK_UNLOCKED;rn pthread_t pid = pthread_self();rnrn if (THREAD_INVALID == plock->pid)rn rn ret = RET_FAILED;rn return ret;rn rnrn //判断是否已经占用了这个锁,如果是,则直接退出,不是则进行下一步rn __asm__ __volatile__(rn "cmpw %1, %0\n"rn "jne 1f\n"rn "call abort\n"rn "1:"rn :"=m" (plock->pid)rn :"q" (pid) rn :"memory", "cc"rn );rnrn __asm__ __volatile__(rn "1:\n"rn "cmpw %1, %0\n"rn "jne 1b\n"rn "lock xaddw %1, %2\n"rn :"=q" (unlock), "=m" (plock->lock)rn :"q" (lock)rn :"memory", "cc"rn );rnrn plock->pid = pid;rnrn return RET_SUCCESS;rnrnrnint spinlock_trywait(PSPINLOCK plock)rnrn int ret = RET_SUCCESS;rn pthread_t pid = pthread_self();rn lock_t lock = LOCK_LOCKED;rn lock_t unlock = LOCK_UNLOCKED;rnrn if (THREAD_INVALID == plock->pid)rn rn ret = RET_FAILED;rn return ret;rn rn rn __asm__ __volatile__(rn "cmpw %1, %0\n"rn "je 2f\n"rn "jne 1f\n"rn "1:\n"rn "addw %2, %3\n"rn "2:\n"rn : "=q" (pid), "=m" (plock->pid),"=m" (ret)rn : "ir" (RET_FAILED) rn :"memory", "cc"rn );rnrn if (RET_FAILED == ret)rn rn return ret;rn rnrn __asm__ __volatile__(rn "cmp %1, %0\n"rn "jne 1f\n"rn "lock xaddw %1, %3\n"rn "jmp 2f\n"rn "1:\n"rn "mv %%eax, %4\n"rn "mv %2, %%eax\n"rn "2:\n"rn : "=q" (unlock), "=m" (plock->lock), "=m" (ret)rn : "q" (lock), "ir" (RET_FAILED)rn : "memory", "cc"rn );rnrn if (RET_FAILED == ret)rn rn return ret;rn rn elsern rn plock->pid = pid;rn return ret;rn rnrnrnint spinlock_post(PSPINLOCK plock)rnrn pthread_t pid = pthread_self();rn lock_t unlock = LOCK_UNLOCKED;rn lock_t lock = LOCK_LOCKED;rnrn if (pid != plock->pid)rn rn return RET_SUCCESS;rn rnrn __asm__ __volatile__(rn "cmp %1, %0\n"rn "je 1f\n"rn "call abort\n"rn "1:\n"rn "mvw %%eax, %2\n"rn "mvw %1, %%eax\n"rn :"=q"(lock), "=m" (plock->lock)rn :"p" (unlock)rn :"memory", "cc"rn );rnrn return RET_SUCCESS;rnrnrnint spinlock_destroy(PSPINLOCK plock)rnrn if (THREAD_DEFAULT == plock->pid && LOCK_UNLOCKED == plock->lock)rn rn plock->pid = THREAD_INVALID;rn rn return RET_SUCCESS;rn rnrn return RET_FAILED;rnrn[/code]rn这段代码凡是汇编的地方几乎都有错.rngcc -g spinlock.c main.c -lpthread -I.rnspinlock.c: Assembler messages:rnspinlock.c:30: Warning: using `%dx' instead of `%edx' due to `w' suffixrnspinlock.c:41: Warning: using `%ax' instead of `%eax' due to `w' suffixrnspinlock.c:43: Error: operand size mismatch for `xadd'rnspinlock.c:68: Warning: using `%ax' instead of `%eax' due to `w' suffixrnspinlock.c:72: Error: operand size mismatch for `add'rnspinlock.c:87: Error: operand size mismatch for `xadd'rnspinlock.c:90: Error: no such instruction: `mv %eax,$-1'rnspinlock.c:91: Error: no such instruction: `mv -24(%ebp),%eax'rnspinlock.c:125: Error: no such instruction: `mvw %eax,%eax'rnspinlock.c:126: Error: no such instruction: `mvw (%edx),%eax'rn各位大神指点则个.小的不胜感激啊.rn小的可能不在线等哈.不过看到的第一时间,一定回复.
- 帮忙看下这段java程序
- //根据用户名和密码判断用户登录的方法，返回的是一个UserBean类型rn public UserBean checkUsersLogin(String userName,String userPwd)rn UserBean ub=null;rn //调用checkParameter方法判断输入的用户名和密码是不是含有非法字符rn if(!checkParameter(userName+userPwd))rn userName="null";rn userPwd="null";rn rn rn rn try rn String sql="select count(*) from user where userName=?and userPwd=?";[color=#FF0000]1:这句count(*)是啥意思？[/color]rn prepar=conn.prepareStatement(sql);//获得Statement对象rn prepar.setString(1, userName);rn prepar.setString(2, userPwd);rn rs=prepar.executeQuery();//执行SQL语句，获得结果集rn if(rs.next())[color=#FF0000]3.从这句开始彻底不明白他想要干什么？[/color]rn if(rs.getInt(1)>0)rn ub=this.getUser(userName);//调用getUser方法获得一个用户rn elsern ub=null;rn rn rn catch (SQLException e) rn // TODO 自动生成 catch 块rn e.printStackTrace();rn rn return ub;rn rn rn rn //提取登录用户信息rn private UserBean getUser(String userName) rn // TODO 自动生成方法存根rn UserBean ub=new UserBean();rn try rn String sql="select * from user where userName=?";rn prepar=conn.prepareStatement(sql);rn prepar.setString(1, userName);rn rs=prepar.executeQuery();rn while(rs.next())//提取用户集合记录[color=#FF0000]2.这句什么意思呢？提取同名用户集合？那下面的操作有什么意义呢？他永远set就去的都是while循环中最后一个对象。[/color] rn ub.setUserName(rs.getString("userName"));rn ub.setUserPwd(rs.getString("userPwd"));rn ub.setUserId(rs.getLong("userId"));rn catch (SQLException e) rn // TODO 自动生成 catch 块rn e.printStackTrace();rn rn rn return ub;rn rnrn private boolean checkParameter(String para) rn // TODO 自动生成方法存根rn int flag=0;rn flag+=para.indexOf("'")+1;rn flag+=para.indexOf(";")+1;rn flag+=para.indexOf("1=1")+1;rn flag+=para.indexOf("|")+1;rn flag+=para.indexOf("")+1;rn if(flag!=0)rn System.out.println("提交了非法字符！！！");rn return false;rn rn return true;rn
- 帮忙看下这段 代码。
- 项目使用的是mvc1.0 rnrn一个类继承Controller实现抽象方法OnActionExecuting. 大家帮我看下，谢谢。rnrn protected override void OnActionExecuting(ActionExecutingContext filterContext)rn rnrn string[] arr = Request.Url.Host.Split('/');rn string newEventName = arr[0].ToLower();rnrn //if (newEventName == "manage")rn //rn // Response.Redirect("manage");rn //rn if (!filterContext.HttpContext.User.Identity.IsAuthenticated || Session["user"] == null)rn rn //use the current url for the redirectrn string redirectOnSuccess = filterContext.HttpContext.Request.Url.AbsolutePath;rnrn //send them off to the login pagern string redirectUrl = string.Format("?ReturnUrl=0", redirectOnSuccess);rn string loginUrl = FormsAuthentication.LoginUrl + redirectUrl;rn filterContext.HttpContext.Response.Redirect(loginUrl, true);rnrn rnrn#if DEBUGrn this.EventList = new EventRepository().GetEventList(1);rn#elsern if (this.CurrentCompany != null)rn rn this.EventList = new EventRepository().GetEventList(this.CurrentCompany.id);rn rn#endifrnrn if (this.EventList != null && this.EventList.Count > 0)rn rnrn if (this.CurrentEvent == null ||rn newEventName != this.CurrentEvent.eventName.ToLower())rn rn this.CurrentEvent = this.EventList.Where(e => e.eventName.ToLower() == newEventName).SingleOrDefault();rnrn if (this.CurrentEvent == null)rn rn this.CurrentEvent = this.EventList[0];rn _isRedirectSubDomain = true;rn //filterContext.Result = JavaScript("Banner");rn rn rnrn ViewData["EventList"] = new SelectList(this.EventList, "id", "eventname", this.CurrentEvent.id);rnrn base.OnActionExecuting(filterContext);rn rn
- 帮忙看下这段代码！！
- using System;rnrnnamespace ConsoleApplication1rnrn /// rn /// Class1 的摘要说明。rn /// rn class Class1rn rn enum Temperaturesrn rn FreezingPoint = 32,rn BoilingPoint = 212,rn SwimmingWeathet = 27rn rnrn rn /// rn /// 应用程序的主入口点。rn /// rn [STAThread]rn static void Main(string[] args)rn rn rnrn System.Console.WriteLine("Freezing point of water :0",(int)Temperatures.FreezingPoint);rnrn System.Console.WriteLine("BoilingPoint: 0",(int) Temperatures.BoilingPoint);rn rn rn rnrnrn为什么把enum Temperatures放到Main中定义就会出错？rn
- 编写一段代码，其功能是打印代码本身
- 编写一段代码，其功能是打印代码本身#includemain(){char *c="#include%cmain()%c{%cchar *c=%c%s%c;%cprintf(c,10,10,10,34,c,34,10,10);%c}";printf(c,10,10,10,34,c,34,10,10);}以上代码来自：编写一段代码，其功能是打印代码本身。该代码将自身编为单行的字符串然后打印，并使用AS
- 7种JAVASCRIPT加密方法
- JAVASCRIPT加密方法，JS加密解密综述（7种） 一：最简单的加密解密 对于JAVASCRIPT函数escape()和unescape()想必是比较了解啦（很多网页加密在用它们），分别是编码和解码字符串，比如例子代码 用escape()函数加密后变为如下格式： alert%28%22%u9ED1%u5BA2%u9632%u7EBF%22%29%3B
- 版主求帮忙看下一个js加密的
- 一个网站我想模拟post登陆，但是他账号+密码+验证码，然后一起加密了。每次密码都不同，让我无法post，求帮忙把下面的js加密换成C#里面的加密。本人js不是很好。辛苦了。rn下面是他js的文件代码[code=javascript]rnrnrn/* md5.js - MD5 Message-Digestrn * Copyright (C) 1999,2002 Masanao Izumo rn * Version: 2.0.0rn * LastModified: May 13 2002rn *rn * This program is free software. You can redistribute it and/or modifyrn * it without any warranty. This library calculates the MD5 based on RFC1321.rn * See RFC1321 for more information and algorism.rn */rnrn/* Interface:rn * md5_128bits = MD5_hash(data);rn * md5_hexstr = MD5_hexhash(data);rn */rnrn/* ChangeLogrn * 2002/05/13: Version 2.0.0 releasedrn * NOTICE: API is changed.rn * 2002/04/15: Bug fix about MD5 length.rn */rnrnrn// md5_T[i] = parseInt(Math.abs(Math.sin(i)) * 4294967296.0);rnvar MD5_T = new Array(0x00000000, 0xd76aa478, 0xe8c7b756, 0x242070db,rn 0xc1bdceee, 0xf57c0faf, 0x4787c62a, 0xa8304613,rn 0xfd469501, 0x698098d8, 0x8b44f7af, 0xffff5bb1,rn 0x895cd7be, 0x6b901122, 0xfd987193, 0xa679438e,rn 0x49b40821, 0xf61e2562, 0xc040b340, 0x265e5a51,rn 0xe9b6c7aa, 0xd62f105d, 0x02441453, 0xd8a1e681,rn 0xe7d3fbc8, 0x21e1cde6, 0xc33707d6, 0xf4d50d87,rn 0x455a14ed, 0xa9e3e905, 0xfcefa3f8, 0x676f02d9,rn 0x8d2a4c8a, 0xfffa3942, 0x8771f681, 0x6d9d6122,rn 0xfde5380c, 0xa4beea44, 0x4bdecfa9, 0xf6bb4b60,rn 0xbebfbc70, 0x289b7ec6, 0xeaa127fa, 0xd4ef3085,rn 0x04881d05, 0xd9d4d039, 0xe6db99e5, 0x1fa27cf8,rn 0xc4ac5665, 0xf4292244, 0x432aff97, 0xab9423a7,rn 0xfc93a039, 0x655b59c3, 0x8f0ccc92, 0xffeff47d,rn 0x85845dd1, 0x6fa87e4f, 0xfe2ce6e0, 0xa3014314,rn 0x4e0811a1, 0xf7537e82, 0xbd3af235, 0x2ad7d2bb,rn 0xeb86d391);rnrnvar MD5_round1 = new Array(new Array( 0, 7, 1), new Array( 1,12, 2),rn new Array( 2,17, 3), new Array( 3,22, 4),rn new Array( 4, 7, 5), new Array( 5,12, 6),rn new Array( 6,17, 7), new Array( 7,22, 8),rn new Array( 8, 7, 9), new Array( 9,12,10),rn new Array(10,17,11), new Array(11,22,12),rn new Array(12, 7,13), new Array(13,12,14),rn new Array(14,17,15), new Array(15,22,16));rnrnvar MD5_round2 = new Array(new Array( 1, 5,17), new Array( 6, 9,18),rn new Array(11,14,19), new Array( 0,20,20),rn new Array( 5, 5,21), new Array(10, 9,22),rn new Array(15,14,23), new Array( 4,20,24),rn new Array( 9, 5,25), new Array(14, 9,26),rn new Array( 3,14,27), new Array( 8,20,28),rn new Array(13, 5,29), new Array( 2, 9,30),rn new Array( 7,14,31), new Array(12,20,32));rnrnvar MD5_round3 = new Array(new Array( 5, 4,33), new Array( 8,11,34),rn new Array(11,16,35), new Array(14,23,36),rn new Array( 1, 4,37), new Array( 4,11,38),rn new Array( 7,16,39), new Array(10,23,40),rn new Array(13, 4,41), new Array( 0,11,42),rn new Array( 3,16,43), new Array( 6,23,44),rn new Array( 9, 4,45), new Array(12,11,46),rn new Array(15,16,47), new Array( 2,23,48));rnrnvar MD5_round4 = new Array(new Array( 0, 6,49), new Array( 7,10,50),rn new Array(14,15,51), new Array( 5,21,52),rn new Array(12, 6,53), new Array( 3,10,54),rn new Array(10,15,55), new Array( 1,21,56),rn new Array( 8, 6,57), new Array(15,10,58),rn new Array( 6,15,59), new Array(13,21,60),rn new Array( 4, 6,61), new Array(11,10,62),rn new Array( 2,15,63), new Array( 9,21,64));rnrnfunction MD5_F(x, y, z) return (x & y) | (~x & z); rnfunction MD5_G(x, y, z) return (x & z) | (y & ~z); rnfunction MD5_H(x, y, z) return x ^ y ^ z; rnfunction MD5_I(x, y, z) return y ^ (x | ~z); rnrnvar MD5_round = new Array(new Array(MD5_F, MD5_round1),rn new Array(MD5_G, MD5_round2),rn new Array(MD5_H, MD5_round3),rn new Array(MD5_I, MD5_round4));rnrnfunction MD5_pack(n32) rn return String.fromCharCode(n32 & 0xff) +rn String.fromCharCode((n32 >>> 8) & 0xff) +rn String.fromCharCode((n32 >>> 16) & 0xff) +rn String.fromCharCode((n32 >>> 24) & 0xff);rnrnrnfunction MD5_unpack(s4) rn return s4.charCodeAt(0) |rn (s4.charCodeAt(1) << 8) |rn (s4.charCodeAt(2) << 16) |rn (s4.charCodeAt(3) << 24);rnrnrnfunction MD5_number(n) rn while (n < 0)rn n += 4294967296;rn while (n > 4294967295)rn n -= 4294967296;rn return n;rnrnrnfunction MD5_apply_round(x, s, f, abcd, r) rn var a, b, c, d;rn var kk, ss, ii;rn var t, u;rnrn a = abcd[0];rn b = abcd[1];rn c = abcd[2];rn d = abcd[3];rn kk = r[0];rn ss = r[1];rn ii = r[2];rnrn u = f(s[b], s[c], s[d]);rn t = s[a] + u + x[kk] + MD5_T[ii];rn t = MD5_number(t);rn t = ((t<>>(32-ss)));rn t += s[b];rn s[a] = MD5_number(t);rnrnrnfunction MD5_hash(data) rn var abcd, x, state, s;rn var len, index, padLen, f, r;rn var i, j, k;rn var tmp;rnrn state = new Array(0x67452301, 0xefcdab89, 0x98badcfe, 0x10325476);rn len = data.length;rn index = len & 0x3f;rn padLen = (index < 56) ? (56 - index) : (120 - index);rn if(padLen > 0) rn data += "\x80";rn for(i = 0; i < padLen - 1; i++)rn data += "\x00";rn rn data += MD5_pack(len * 8);rn data += MD5_pack(0);rn len += padLen + 8;rn abcd = new Array(0, 1, 2, 3);rn x = new Array(16);rn s = new Array(4);rnrn for(k = 0; k < len; k += 64) rn for(i = 0, j = k; i < 16; i++, j += 4) rn x[i] = data.charCodeAt(j) |rn (data.charCodeAt(j + 1) << 8) |rn (data.charCodeAt(j + 2) << 16) |rn (data.charCodeAt(j + 3) << 24);rn rn for(i = 0; i < 4; i++)rn s[i] = state[i];rn for(i = 0; i < 4; i++) rn f = MD5_round[i][0];rn r = MD5_round[i][1];rn for(j = 0; j < 16; j++) rn MD5_apply_round(x, s, f, abcd, r[j]);rn tmp = abcd[0];rn abcd[0] = abcd[3];rn abcd[3] = abcd[2];rn abcd[2] = abcd[1];rn abcd[1] = tmp;rn rn rnrn for(i = 0; i < 4; i++) rn state[i] += s[i];rn state[i] = MD5_number(state[i]);rn rn rnrn return MD5_pack(state[0]) +rn MD5_pack(state[1]) +rn MD5_pack(state[2]) +rn MD5_pack(state[3]);rnrnrnfunction MD5_hexhash(data) rn var i, out, c;rn var bit128;rnrn bit128 = MD5_hash(data);rn out = "";rn for(i = 0; i < 16; i++) rn c = bit128.charCodeAt(i);rn out += "0123456789abcdef".charAt((c>>4) & 0xf);rn out += "0123456789abcdef".charAt(c & 0xf);rn rn return out;rnrnrnrn[/code]rn他调用的代码是[code=javascript]rnfunction pwdmd5()rn rn var pwd=document.getElementById("passwords");rn var checkcode=document.getElementById("checkcode");rn var username=document.getElementById("name");rn rn var mm=MD5_hexhash(username.value+pwd.value);rn mm=MD5_hexhash(mm+checkcode.value);rn rn var keystr="";rn rn for(i=0;i<8;i++)rn rn keystr+=MD5_hexhash(mm.substr(i*4,8));rn rn pwd.value=MD5_hexhash(keystr);rn return true;rn rn rn rnrn[/code]
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We can't do anything.rn if (CurrentLine == NULL)rn rn return FALSE;rn rn rn // If field is odd we will offset it down 1 line to avoid jitter TRB 1/21/01rn if (pInfo->PictureHistory[0]->Flags & PICTURE_INTERLACED_ODD)rn rn if (pInfo->CpuFeatureFlags & FEATURE_SSE)rn rn pInfo->pMemcpy(lpOverlay, CurrentLine, pInfo->LineLength); // extra copy of first linern lpOverlay += pInfo->OverlayPitch; // and offset out output ptrrn for (i = 0; i < pInfo->FieldHeight - 1; i++)rn rn memcpyBOBSSE(lpOverlay, lpOverlay + pInfo->OverlayPitch,rn CurrentLine, pInfo->LineLength);rn lpOverlay += 2 * pInfo->OverlayPitch;rn CurrentLine += Pitch;rn rn pInfo->pMemcpy(lpOverlay, CurrentLine, pInfo->LineLength); // only 1 copy of last linern rn rn rn elsern rn if (pInfo->CpuFeatureFlags & FEATURE_SSE)rn rn for (i = 0; i < pInfo->FieldHeight; i++)rn rn memcpyBOBSSE(lpOverlay, lpOverlay + pInfo->OverlayPitch,rn CurrentLine, pInfo->LineLength);rn lpOverlay += 2 * pInfo->OverlayPitch;rn CurrentLine += Pitch;rn rn rn rn rn // need to clear up MMX registersrn _asmrn rn emmsrn rn return TRUE;rnrnrn[/code]rnrn其中的TDeinterlaceInfo* 如下rn[code=C/C++]rntypedef structrnrn /** set to version of this structurern used to avoid crashing with incompatable versionsrn */rn DWORD Version;rnrn /** The most recent pictures rn PictureHistory[0] is always the most recent.rn Pointers are NULL if the picture in question isn't valid, e.g. becausern the program just started or a picture was skipped.rn */rn TPicture* PictureHistory[MAX_PICTURE_HISTORY];rnrn /// Current overlay buffer pointer.rn BYTE *Overlay;rnrn /// The part of the overlay that we actually showrn RECT SourceRect;rnrn /** which frame are we on nowrn \todo remove thisrn */rn int CurrentFrame;rnrn /// Overlay pitch (number of bytes between scanlines).rn DWORD OverlayPitch;rnrn /** Number of bytes of actual data in each scanline. May be less thanrn OverlayPitch since the overlay's scanlines might have alignmentrn requirements. Generally equal to FrameWidth * 2.rn */rn DWORD LineLength;rnrn /// Number of pixels in each scanline.rn int FrameWidth;rnrn /// Number of scanlines per frame.rn int FrameHeight;rnrn /** Number of scanlines per field. FrameHeight / 2, mostly forrn cleanliness so we don't have to keep dividing FrameHeight by 2.rn */rn int FieldHeight;rnrn /// Results from the NTSC Field comparern long FieldDiff;rn /// Results of the PAL Mode deinterlace detectrn long CombFactor;rn /// Function pointer to optimized memcpy functionrn MEMCPY_FUNC* pMemcpy;rn /// What Type of CPU are we runningrn long CpuFeatureFlags;rn /// Are we behind with processingrn BOOL bRunningLate;rn /// Are we behind with processingrn BOOL bMissedFrame;rn /// Do we want to flip accuratlyrn BOOL bDoAccurateFlips;rn /// How big the source will end uprn RECT DestRect;rnrn /** distance between lines in imagern need not match the pixel widthrn */rn long InputPitch;rn TDeinterlaceInfo;rnrnrntypedef structrnrn // pointer to the start of data for this picturern BYTE* pData;rn // see PICTURE_ flagsrn DWORD Flags;rn // is this the first picture in a new seriesrn // use this flag to indicate changes to any of the rn // paramters that are assumed to be fixed likern // timings or pixel widthrn BOOL IsFirstInSeries;rn TPicture;rnrn[/code]rnrn其中的 memcpyBOBSSE是这样：关键就是这个看不懂：rn[code=C/C++]rnvoid memcpyBOBSSE(void *Dest1, void *Dest2, void *Src, size_t nBytes)rnrn __asmrn rn mov esi, dword ptr[Src]rn mov edi, dword ptr[Dest1]rn mov ebx, dword ptr[Dest2]rn mov ecx, nBytesrn shr ecx, 7 // nBytes / 128rnalign 8rnCopyLoop:rn movaps xmm0, xmmword ptr[esi]rn movaps xmm1, xmmword ptr[esi+16*1]rn movaps xmm2, xmmword ptr[esi+16*2]rn movaps xmm3, xmmword ptr[esi+16*3]rn movaps xmm4, xmmword ptr[esi+16*4]rn movaps xmm5, xmmword ptr[esi+16*5]rn movaps xmm6, xmmword ptr[esi+16*6]rn movaps xmm7, xmmword ptr[esi+16*7]rn movntps xmmword ptr[edi], xmm0rn movntps xmmword ptr[edi+16*1], xmm1rn movntps xmmword ptr[edi+16*2], xmm2rn movntps xmmword ptr[edi+16*3], xmm3rn movntps xmmword ptr[edi+16*4], xmm4rn movntps xmmword ptr[edi+16*5], xmm5rn movntps xmmword ptr[edi+16*6], xmm6rn movntps xmmword ptr[edi+16*7], xmm7rn movntps xmmword ptr[ebx], xmm0rn movntps xmmword ptr[ebx+16*1], xmm1rn movntps xmmword ptr[ebx+16*2], xmm2rn movntps xmmword ptr[ebx+16*3], xmm3rn movntps xmmword ptr[ebx+16*4], xmm4rn movntps xmmword ptr[ebx+16*5], xmm5rn movntps xmmword ptr[ebx+16*6], xmm6rn movntps xmmword ptr[ebx+16*7], xmm7rn add esi, 128rn add edi, 128rn add ebx, 128rn dec ecxrn jne near CopyLooprnrn mov ecx, nBytesrn and ecx, 127rn cmp ecx, 0rn je EndCopyLooprnalign 8rnCopyLoop2:rn mov dl, byte ptr[esi] rn mov byte ptr[edi], dlrn mov byte ptr[ebx], dlrn inc esirn inc edirn inc ebxrn dec ecxrn jne near CopyLoop2rnEndCopyLoop:rn rnrnrn[/code]
- 帮忙看下这段程序问题在哪里？
- 是关于给树控件加tooltip的。我先是在OnCreate函数里加入这段代码rn HTREEITEM hItem,hSubItem;rn CTreeCtrl* pTree = (CTreeCtrl*)GetDlgItem(IDC_TREECTRL);rn hItem = pTree->InsertItem("ºÃÓÑ",TVI_ROOT);rn hSubItem = pTree->InsertItem(Contactors[0],hItem);rn hSubItem = pTree->InsertItem(Contactors[1],hItem,hSubItem);rn hSubItem = pTree->InsertItem(Contactors[2],hItem,hSubItem);rn hSubItem = pTree->InsertItem(Contactors[5],hItem,hSubItem);rn hSubItem = pTree->InsertItem(Contactors[6],hItem,hSubItem);rn pTree->ModifyStyle(TVS_NOTOOLTIPS, TVS_INFOTIP); rn if (!m_ctrlTree.Create(WS_CHILD|WS_VISIBLE|TVS_HASLINES|TVS_HASBUTTONS|TVS_LINESATROOT|TVS_SHOWSELALWAYS|TVS_INFOTIP, CRect(0, 0, 0, 0), this, IDC_TREECTRL))rn rn TRACE0("Failed to create instant bar child\n");rn return -1;rn rn其次加入映射消息声明，如下所示:rnvoid CMainFrame::OnGetInfoTip(NMHDR* pNMHDR, LRESULT* pResult) rn CTreeCtrl* pTree = (CTreeCtrl*)GetDlgItem(IDC_TREECTRL);rn *pResult = 0;rn NMTVGETINFOTIP* pTVTipInfo = (NMTVGETINFOTIP*)pNMHDR;rn LPARAM itemData = (DWORD) pTVTipInfo->lParam；rn HTREEITEM hItem = pTVTipInfo->hItem;rn CString tip;rn HTREEITEM hRootItem = m_chassisTree.GetRootItem();rn if (hRootItem != pTVTipInfo->hItem)rnrn tip = "显示字";rnrn elsernrn tip = "显示的字";rnrn strcpy(pTVTipInfo->pszText, (LPCTSTR) tip);rnrn以上代码是参考的别人的，我加了之后，编译通过，但是运行后我把鼠标移到树控件处就弹出一个报错窗口。我在给消息处理函数下断点，发现运行到HTREEITEM hRootItem = m_chassisTree.GetRootItem();时报错窗口弹出。rn请问是哪里出问题，该怎么改？？rn
- 大家帮忙看下这段代码
- class ButtonPanel extends JPanelrnrnrn /**rn * rn */rn private static final long serialVersionUID = 31126401022136278L;rnrn public ButtonPanel()rn rn JButton yellowButton = new JButton("yellow");rn JButton blueButton = new JButton("blue");rn add(yellowButton);rn add(blueButton);rn rnrnrn为什么在eclips里面编译的时候要加 rn private static final long serialVersionUID = 31126401022136278L;rn在其jcreator中却不用加，请高手指点
- js的常见的三种密码加密方式-MD5加密、Base64加密和解密和sha1加密详解总结
- 写在前面写前端的时候，很多的时候是避免不了注册这一关的，但是一般的注册是没有任何的难度的，无非就是一些简单的获取用户输入的数据，然后进行简单的校验以后调用接口，将数据发送到后端，完成一个简单的注册的流程，那么一般来说，密码是不做加密的。但是也有一些数据库里面存放的是加密后的密码，这样有一个比较安全的地方在于，即使黑客将用户输入的文本密码得到了，也不知道具体是什么，因为密码是经过加密的。今天就简单的...
- 大神帮忙看下这段代码
- public class Test rn static boolean foo(char c) rn System.out.print(c);rn return true;rn rn public static void main( String[] argv ) rn int i =0;rn for ( foo('A'); foo('B')&&(i);rn rn rn rn输出结果ABDCBDCBrn为什么
- 帮忙看下这段代码对不对
- [code=C#]rn string sqlks="select distinct(month) as month from month where kaohefangshi='1'";//查询考核方式为月的所有月份列表,然后根据月份列表批量增加相应的记录rn SqlCommand cmdsqlks=new SqlCommand(sqlks,conn);rn SqlDataReader reader1=cmdsqlks.ExecuteReader();rn while(reader.Read())rn rn string intsertxjl="insert into month(khdx,khdxfx,khdxfxxh,khnr,fz,jf,kf,khdw,jcfz,mkh,qkh,ykh,kaohefangshi,month) select khdx,khdxfx,khdxfxxh,khnr,fz,jf,kf,khdw,jcfz,mkh,qkh,ykh,kaohefangshi,'"+reader1["month"].ToString().Trim()+"' where mkh='0' and qkh='1' and month='本月'";rn SqlCommand cmdintsertxjl=new SqlCommand(intsertxjl,conn);rn cmdintsertxjl.ExecuteNonQuery();rn reader.NextResult();rn rn[/code]rn关键是循环里边的内容是不是可以全部执行完。。或者有更好的语句能够把整个过程用一个语句完成的也可以rn
- 帮忙看下这段javascript代码
- 在什么条件下它会调用ERR_Noneplayer这个变量rnrn
- WPF，帮忙看下这段代码
- [code=html]rnrn rn rn
- 请帮忙看下这段代码
- 求用户指定范围内的数的和，一直提示编译错误，找了半天也找不出哪错了，，，如果这段代码省略设置上界和下界的IF设置该怎么改？rnrn#include rnint main()rnrn int v1,v2;rn std::cin>>v1;v2;rn int lower,upper;rn if (v1
- 帮忙看下这段程序的错误
- 目的：寻找两个字符串中最大的公共子串。rn已经通过V6编译，但是运行会提示出错。rn基本思路是构造动态的矩阵，代码如下，请高手看看错在什么地方，应该怎样修改。rn谢谢！rn#include rn#include rn#include rnrnusing namespace std;rnrnvoid search(string strr1,string strr2);//寻找最大相同字符串并输出rnrnint main()rnstring a,b;rncout<<>a>>b;rnsearch(a,b);rnreturn 0;rnrnvoid search(string strr1,string strr2)rn int i,j,count;rn int num=0;//参变量rn int len1=strr1.size();//求出输入字符串的长度rn int len2=strr2.size();rn int **sign = new int*[len1];//动态二维数组的创建rn for (i=0;i
- 帮忙看下这段代码啥意思?
- #ifdef USE_DOT_Hrn #include rn#elsern #include rn #if !defined( __BORLANDC__ ) || __BORLANDC__ >= 0x0530rn using namespace std; rn #endifrn#endifrnrnrn1 USE_DOT_H 是什么意思 ?rn2 defined( __BORLANDC__ ) || __BORLANDC__ >= 0x0530 是什么意思?rn
- 帮忙看下这段语句怎么改
- 语句如下：rnrnSELECT TaxPayerID, TaxPayerName, iYear, BankName, TaxDeptName, rn (CASE WHEN imonth = '1' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Jan1, (CASE WHEN imonth = '1' THEN taxmoney ELSE 0 END) AS Jan0, rn (CASE WHEN imonth = '2' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Feb1, (CASE WHEN imonth = '2' THEN taxmoney ELSE 0 END) AS Feb0, rn (CASE WHEN imonth = '3' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Mar1, (CASE WHEN imonth = '3' THEN taxmoney ELSE 0 END) AS Mar0, rn (CASE WHEN imonth = '4' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Apr1, (CASE WHEN imonth = '4' THEN taxmoney ELSE 0 END) AS Apr0, rn (CASE WHEN imonth = '5' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS May1, (CASE WHEN imonth = '5' THEN taxmoney ELSE 0 END) AS May0, rn (CASE WHEN imonth = '6' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Jun1, (CASE WHEN imonth = '6' THEN taxmoney ELSE 0 END) AS Jun0, rn (CASE WHEN imonth = '7' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Jul1, (CASE WHEN imonth = '7' THEN taxmoney ELSE 0 END) AS Jul0, rn (CASE WHEN imonth = '8' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Aug1, (CASE WHEN imonth = '8' THEN taxmoney ELSE 0 END) AS Aug0, rn (CASE WHEN imonth = '9' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Sep1, (CASE WHEN imonth = '9' THEN taxmoney ELSE 0 END) AS Sep0, rn (CASE WHEN imonth = '10' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Oct1, (CASE WHEN imonth = '10' THEN taxmoney ELSE 0 END) AS Oct0, rn (CASE WHEN imonth = '11' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Nov1, (CASE WHEN imonth = '11' THEN taxmoney ELSE 0 END) AS Nov0, rn (CASE WHEN imonth = '12' AND CancelOrNot = 20 THEN taxmoney ELSE 0 END) rn AS Dec1, (CASE WHEN imonth = '12' THEN taxmoney ELSE 0 END) AS Dec0,rnFROM V_CancelRep1rnGROUP BY iYear, TaxPayerID, TaxPayerName, BankName, TaxDeptName, TaxMoney, rn iMonth, CancelOrNotrnrn这样统计出来同一单位的信息有多条，如果12个月都有的话就有12条，如下，数值为7月份和8月份的，并非在一行统计，求教请问这样的语句怎么修改rnrn340111849021476 安徽省电力公司合肥供电公司2008 中国工商银行合肥市四牌楼支行 合肥市包河区国家税务局 0 0 0 0 0 0 100 0 0 0 0 0 rn340111849021476 安徽省电力公司合肥供电公司2008 中国工商银行合肥市四牌楼支行 合肥市包河区国家税务局 0 0 0 0 0 0 0 100 0 0 0 0 rn
- 帮忙看下 这段VHDL的错误
- LIBRARY IEEE; rn USE IEEE.STD_LOGIC_1164.ALL;rn USE IEEE.STD_LOGIC_UNSIGNED.ALL;rnENTITY TIME ISrn PORT(REST,SP,CLK :IN STD_LOGIC;rn TI:OUT STD_LOGIC;rn SECOND1,SECOND2,MINITUE1,MINITUE2:OUT STD_LOGIC_VECTOR(3 DOWNTO 0));rn END TIME;rnARCHITECTURE ONE OF TIME ISrn SIGNAL TIMECLK:STD_LOGIC;rn SIGNAL CLK12:STD_LOGIC_VECTOR(3 DOWNTO 0);rn SIGNAL SEC1,SEC2:STD_LOGIC_VECTOR(3 DOWNTO 0);rn SIGNAL MINI1,MINI2:STD_LOGIC_VECTOR(3 DOWNTO 0);rnBEGINrn MINITUE1(3 DOWNTO 0);rn END IF;rn END IF;rn END IF;rn END IF;rn END IF;rn END IF;rn END PROCESS; rn END ONE; rnrn为什么提示 non-locally-static attribute names are not support这个错误
- 帮忙看下这段php代码怎么改？
- 下面是一段早期php代码，由于php升级及sql server驱动升级rn目前是php 5.2.14 + Sql serve 2008，所以有些用法不同了，像rn$res = mssql_query($sql, $link);改为$res = sqlsrv_query($conn,$sql);rnrn[b]但mssql_fetch_row不知道如何改？[/b]rnrn就这是句怎么改？rn[code=PHP] while ($row = mssql_fetch_row($res))rn $vals[strtolower(str_replace($search, '', $row[0]))] = (empty($row[1]) ? '0' : $row[1]);rn rn[/code]rnrn[code=PHP] #$res = mssql_query($sql, $link);rn $res = sqlsrv_query($conn,$sql);rnrn $search = array(' ', '/sec', '(KB)', '/', '-');rnrn while ($row = mssql_fetch_row($res))rn $vals[strtolower(str_replace($search, '', $row[0]))] = (empty($row[1]) ? '0' : $row[1]);rn rnrn $vals['buffercachehitratio'] = $vals['buffercachehitratio'] / $vals['buffercachehitratiobase'] * 100;rn $vals['logcachehitratio'] = $vals['logcachehitratio'] / $vals['logcachehitratiobase'] * 100;rn $vals['proccachehitratio'] = $vals['cachehitratio'] / $vals['cachehitratiobase'] * 100;rn $vals['memoryhitratio'] = $vals['totalservermemory'] / $vals['targetservermemory'] * 100;rnrn unset($vals['buffercachehitratiobase'], $vals['logcachehitratiobase'], $vals['cachehitratiobase'], $vals['cachehitratio']);rn[/code]rn
我们是很有底线的