bb=[(1,‘a’,"this"),(2,'b',"that"),(3,'c',None)]
>>> b=[(1,'a',"this"),(2,'b',"that"),(3,'c',None)] >>> sorted(bb, key=lambda x: x[2] or chr(255)*10 ) [(2, 'b', 'that'), (1, 'a', 'this'), (3, 'c', None)] >>>
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