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stacksoverflow 2018-06-19
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好吧，当我没说。
hongming09 2018-06-19
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package my.test.testCall2;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Date;
public class Test4 {
private static BufferedReader br;
public static void main(String[] args) {
InputStreamReader isr = new InputStreamReader(System.in);
br = new BufferedReader(isr);
int count;
int score;
while(true){
try {
while(true){
System.out.println("选择答题数 10 20 50");
String s = readConsole();
if("10".equals(s)){
count = 1;
break;
}else if("20".equals(s)){
count = 20;
break;
}else if("50".equals(s)){
count = 50;
break;
}
System.out.println("输入有误");
}
long time = new Date().getTime();
score = 0;
for(int i=0;i< count;i++){
int answer = outQuestion();
System.out.print("请输入答案");
String s = readConsole();
if(String.valueOf(answer).equals(s)){
score+=1;
}
}
time = new Date().getTime()-time;
int min = (int) Math.round(time/60000-0.5);
int sec = Math.round(time%60000/1000);
System.out.println("答对" + score + "题 共" + count + "题 用时" +min +"分" + sec+"秒");
System.out.println("继续答题？y继续 其他退出");
if(!"y".equals(readConsole())){
break;
}
} catch (IOException e) {
System.out.println("系统错误 重新答题");
}
}
}
private static String readConsole() throws IOException {
return br.readLine();
}
private static int outQuestion() throws IOException {
int op = (int) Math.round(Math.random() * 4 - 0.5);
int left = (int) Math.round(Math.random() * 100 - 0.5);
int right = (int) Math.round(Math.random() * 100 - 0.5);
if (op == 0) {
System.out.println("" + (Math.max(left, right) - Math.min(left, right)) + " + " + Math.min(left, right));
return ((Math.max(left, right) - Math.min(left, right)) + Math.min(left, right));
} else if (op == 1) {
System.out.println("" + Math.max(left, right) + " - " + Math.min(left, right));
return (Math.max(left, right) - Math.min(left, right));
} else if (op == 2) {
System.out.println("" + Math.max(Math.round(left / 10), 1) + " × " + Math.max(Math.round(right / 10), 1));
return (Math.max(Math.round(left / 10), 1) * Math.max(Math.round(right / 10), 1));
} else {
System.out.println("" + Math.max(Math.round(left / 10), 1) * Math.max(Math.round(right / 10), 1) + " ÷ "
+ Math.max(Math.round(left / 10), 1));
return (Math.max(Math.round(left / 10), 1) * Math.max(Math.round(right / 10), 1)
/ Math.max(Math.round(left / 10), 1));
}
}
}
maradona1984 2018-06-19
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不难,但不可能有人替你写,这个提供思路自己写
算术题就用最简单的两个数字加运算符号,控制答案在100之内是限制,加减乘除的限制都不一样(加法不能超过100,减法不能有负数,除法不能除以0,小数也最好是有理数,乘法不要超过100)
等等
hongming09 2018-06-19
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漏了句
hongming09 2018-06-19
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html的。
======================
<!DOCTYPE HTML>
<html>
<head>
<title>Untitled</title>
</head>
<body>
<div>
题目数：<select id="count" onchange="countChange()">
<options>
<option value="">选择出题数</option>
<option value="10">10题</option>
<option value="20">20题</option>
<option value="50">50题</option>
</options>
</select>
</div>
<div >
<ol id="questionDiv">
</ol>
</div>
<div >
<input type="button" id="submit" value="交卷" onclick="doSubmit()"></input>
<input type="button" id="re" value="重新答题" onclick="re()"></input>
</div>
<div id="score">
</div>
<script type="text/javascript">
var qDiv = document.getElementById("questionDiv");
var cSelect = document.getElementById("count");
var startTime;
function countChange(){
var html="";
for(var i=0;i<event.target.value;i++){
var op = Math.round(Math.random()*4-0.5);
var left = Math.round(Math.random()*100-0.5);
var right = Math.round(Math.random()*100-0.5);
if(op==0){
html +="<li>" + (Math.max(left,right) - Math.min(left,right)) + " + "+ Math.min(left,right) + " = <input type='text' name='q'></input><input type='hidden' name='a' value='" + ((Math.max(left,right) - Math.min(left,right)) + Math.min(left,right)) +"'></input></li>";
}else if(op==1){
html +="<li>" + Math.max(left,right) + " - "+ Math.min(left,right) + " = <input type='text' name='q'></input><input type='hidden'name='a' value='" + (Math.max(left,right) - Math.min(left,right)) +"'></input></li>";
}else if(op==2){
html +="<li>" + Math.max(Math.round(left/10),1) + " × " + Math.max(Math.round(right/10),1) + " = <input type='text' name='q'></input><input type='hidden' name='a' value='" + (Math.max(Math.round(left/10),1) * Math.max(Math.round(right/10),1)) +"'></input></li>";
}else if(op==3){
html +="<li>" + Math.max(Math.round(left/10),1) * Math.max(Math.round(right/10),1) + " ÷ " + Math.max(Math.round(left/10),1) + " = <input type='text' name='q'></input><input type='hidden' name='a' value='" + (Math.max(Math.round(left/10),1) * Math.max(Math.round(right/10),1) / Math.max(Math.round(left/10),1)) +"'></input></li>";
}
}
qDiv.innerHTML=html;
startTime = new Date().getTime();
}
function doSubmit(){
var q = document.getElementsByName("q"),a=document.getElementsByName("a");
var score = 0;
var scoreA = 100/cSelect.value
for(var i =0;i<q.length;i++){
if(q[i].value==a[i].value){
score +=scoreA;
}
}
var time = Math.round((new Date().getTime() - startTime)/60000-0.5);
var time2 = Math.round((new Date().getTime() - startTime)%60000/1000);
if(score == 100){
alert("恭喜用时：" + time + "分" + time2 + "秒全部答对");
}else{
alert("用时：" + time + "分" + time2 + "秒\n得分：" +score );
}
}
</script>
</body>
</html>
Braska 2018-06-19
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直接随机生成加数和结果，这样就可以不用判断重新生成。
我纯洁全身都纯洁 2018-06-19
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给你个思路吧
1、首先随机生成加减乘除其中的一个符号（查查怎么随机）
2、随机生成两个数字，用上面的符号拼接
3、程序检查下计算结果是否符合范围，不符合就重新随生成两个数字，符合范围就打印输出，等做题的人录入。
4、计算的结果范围：0-100，不能包含小数，除数不能为0等等
ITjavaman 2018-06-19
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谁说的，我就给他写一个
public static void main(String []args) {
System.out.println("这是一个小学算术运算测试程序");
}stacksoverflow 2018-06-19
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打个标签，估计没人理你。
xing4065285 2018-06-19
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