获取当前目录下所有文件中仅包含连续字母和数字的最长字符串

[sunowsir]

大佬们看看哪有问题？

#!/bin/bash

#	File Name:    max_len_str_at_pi1-10.sh
#	Author:       sunowsir
#	Mail:         [e-mail]
#	Created Time: 2018年10月14日 星期日 16时47分44秒

grep -EIHron '[a-zA-Z]+' './' 2> /dev/null | awk -F ':' '
BEGIN{
    first = $0; 
    second = $0; 
    third = $0;
    first_len = length(first); 
    second_len = length(second);
    third_len = length(third);
}
{
    now_str = $0;
    now_length = length($3);
    if (now_length > first_len) {
        third = second; 
        second = first; 
        first = now_str; 
        first_len = now_length; 
    } else if (now_length > second_len && now_length < first_len) {
        third = second;
        second = now_str;
        second_len = now_length;
    } else if (now_length > third_len && now_length < second_len) {
        third = now_str;
        third_len = now_length;
    }
}
END{
    printf(" first : \n %s \n second : \n %s \n third : \n %s \n", first, second, third);
}'

[勤1]

grep -EIHron "[a-zA-Z0-9]+" . |awk -F ':' 'BEGIN{t="";s="";f="";fl=0;sl=0;tl=0}{n=$0;nl=length($3);if(nl>=fl){t=s;tl=sl;s=f;sl=fl;f=n;fl=nl;}else if(nl>=sl){t=s;tl=sl;s=n;sl=nl;}else if(sl>=tl){t=n;tl=nl;}}END{printf("first:\n%s\nsecond:\n%s\nthird:\n%s\n",f,s,t);}'