关于调用一个古老的接口返回401(这是他们正常的流程),而我确想要获得头部信息

[seven7769]

var str2 ="<?xml version=\"1.0\"?><System><SourcePlatformID>aa</SourcePlatformID><DestPlatformID>bb</DestPlatformID><CmdType>Register</CmdType><SN>11</SN><DeviceID>aa</DeviceID></System>";
        HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://ip地址/EGNS/V1.0/System/Register");
        request.Method = "POST";
        request.ContentType = "Application/MANSCDP+xml";
        byte[] bytes = Encoding.UTF8.GetBytes(str2);
        request.ContentLength = bytes.Length;
        using (Stream requestStream = request.GetRequestStream())
        {
            requestStream.Write(bytes, 0, bytes.Length);
            requestStream.Flush();
            requestStream.Close();
        }
        try
        {
            var response = (HttpWebResponse) request.GetResponse();//这句报错;远程服务器返回错误: (401) 未经授权
            
        }
        catch (Exception ex)
        {
            throw;
        }

我问了他们的对接人员,说是返回401错误是正常的,让我们只需要取heard响应头的内容即可
我用postman请求
截图如下


请问在代码里怎么忽略或者捕捉这个401错误,然后获取WWW-Authenticate

[stherix]

catch (WebException ex) { response = (HttpWebResponse)ex.Response; }

[seven7769]

引用 1 楼 stherix 的回复:

catch (WebException ex)
{
response = (HttpWebResponse)ex.Response;
}

感谢,没有想到可以这样