python如何合并字典组成了列表

[看着奢扣]

a = [{'time': '2018-10-31', 'value_1' : '20'},
{'time': '2018-11-01', 'value_1' : '30'}]
b = [{'time': '2018-10-31', 'value_2' : '13'},
{'time': '2018-11-01', 'value_2' : '15'}]

希望按time合并成a，b
[{'time': '2018-10-31', 'value_1' : '20'， 'value_2' : '13'},
{'time': '2018-11-01', 'value_1' : '30'，'value_2' : '15'}]

请 大牛赐教

[qq_41429841]

a = [{'time': '2018-10-31', 'value_1': '20'}, {'time': '2018-11-01', 'value_1': '30'}] b = [{'time': '2018-10-31', 'value_2': '13'}, {'time': '2018-11-01', 'value_2': '15'}] list1 = [] for i in a: for j in b: if i['time'] == j['time']: dict1 = i.copy() dict1.update(j) list1.append(dict1) print(list1)

[手无护鸡之力]

for aa, bb in zip(a, b):
    aa.update(bb)
print(a)

[{'time': '2018-10-31', 'value_1' : '20'， 'value_2' : '13'},
{'time': '2018-11-01', 'value_1' : '30'，'value_2' : '15'}]

[混沌鳄鱼]

如果能严格保证a和b数据对齐，用2楼方法即可。

下面的算法不依赖数据对齐和时间有序，更健壮一些。

a = [{'time': '2018-10-31',  'value_1' : '20'},{'time': '2018-11-01',  'value_1' : '30'}]
b = [{'time': '2018-10-31',  'value_2' : '13'},{'time': '2018-11-01',  'value_2' : '15'}]

from itertools import chain
m = {}
for d in chain(a,b):
    time = d['time']
    if time in m:
        m[time].update(d)
    else:
        m[time] = dict(d)

print(list(m.values()))

# [{'time': '2018-10-31', 'value_1': '20', 'value_2': '13'}, {'time': '2018-11-01', 'value_1': '30', 'value_2': '15'}]