c语言while循环在指定字符时结束

[Moliay]

苦涩 为啥不能接收到我最后的flag求教大佬

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
int a, b, c,i,flag1;
char s,flag;
flag = 'YES';

printf("***************\n");
printf("请选择运算符:\n");
printf("加法运算，请输入“+”;\n");
printf("减法运算，请输入“-”;\n");
printf("乘法运算，请输入“*”;\n");
printf("除法运算，请输入“/”;\n");
printf("***************\n");

while (flag != 'N')
{
if (flag != 'YES')
{
printf("请再次选择运算方式：");
}
flag1 = 1;
scanf_s("%c", &s);
srand((unsigned)time(NULL));
a = rand() % 100 + 1;
b = rand() % 100 + 1;

switch (s)
{
case '+':c = a + b; break;
case '-':c = a - b; break;
case '*':c = a * b; break;
case '/':c = a / b; break;
default:
{
printf("输入有误！");
flag1 = 0;
}
}
if (flag1)
{
printf("%d%c%d\n请输入运算结果\n", a, s, b);
scanf_s("%d", &i);
if (i == c)
printf("你很棒，加油！");
else
printf("很遗憾！");
}
printf("\n继续请输入Y，退出输入N\n");
scanf_s("%c",&flag);
scanf_s("%c", &flag);
}
system("pause");
return 0;
}

[@风轻云淡_]

确实能过编译，重点在他用的单引号不是双引号，编译器就给它自动截断了，和'Y'一样，，如下简单修改下即可。

if (flag1)
{
    printf("%d%c%d\n请输入运算结果\n", a, s, b);
    scanf_s("%d", &i);
    getchar();//这里加一个getchar()吸收掉缓冲区的回车
    if (i == c)
        printf("你很棒，加油！");
    else
        printf("很遗憾！");
}
printf("\n继续请输入Y，退出输入N\n");
scanf_s("%c",&flag);
//scanf_s("%c", &flag);  这里去掉

[Moliay]

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{
int n1, n2, answer, input,flag1;
char flag,c;
flag = 'y';

printf("请输入相应数字选择运算方式：\n1.加法运算\n2.减法运算\n3.乘法运算\n4.除法运算\n");
while (flag != 'N')
{
flag1 = 1;
if (flag != 'y')
{
printf("请再次选择运算方式：\n");
}
srand(time(NULL));
n1 = rand() % 100 + 1;
n2 = rand() % 100 + 1;
scanf_s("%d",&c);
switch (c)
{
case 1:{
answer = n1 + n2;
c = '+';
break;
}
case 2: {
answer = n1 - n2;
c = '-';
break;
}
case 3: {
answer = n1 * n2;
c = '*';
break;
}
case 4: {
answer = n1 / n2;
c = '/';
break;
}
default:{
printf("输入有误！\n");
flag1 = 0;
}
}

if (flag1) {
printf("%d%c%d\n请输入结果：\n",n1,c,n2);
scanf_s("%d",&input);
if (input == answer) printf("你很棒！\n");
else printf("有点遗憾，继续加油！\n");
}
printf("继续游戏输入Y，退出输入N\n");
scanf_s("%c",&flag);
//flag = getchar();
}
system("pause");
return 0;
}

[Moliay]

大佬请赐教

[Moliay]

自我感觉良好 其实结果想狗屎系列

[super_admi]

我看了下，觉得你想要的效果应该是这样的：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>

#define NUMBER_COUNT 2

int main()
{
	int   numbers[NUMBER_COUNT];
	int   i, value, input;
	char  key = '\0';
	char* opt = "+-*/";
	printf("请输入相应数字选择运算方式(ESC退出)：\n1.加法运算\n2.减法运算\n3.乘法运算\n4.除法运算\n");
	while ((key = _getch()) != 0x1b) //0x1b: ESC 
	{
		srand(time(NULL));
		for(i = 0; i < NUMBER_COUNT; i++)
			numbers[i] = rand() % 100 + 1;
		switch (key)
		{
		case '1':
			value = numbers[0] + numbers[1];
			break;
		case '2':
			value = numbers[0] - numbers[1];
			break;
		case '3':
			value = numbers[0] * numbers[1];
			break;
		case '4':
			value = numbers[0] / numbers[1];
			break;
		default:
			break;
		}
		printf("\n%d%c%d\n请输入结果：\n", numbers[0],opt[key - '1'],numbers[1]);
		scanf_s("%d",&input);
		printf("%s", value == input ? "你很棒！\n" : "有点遗憾，继续加油！\n");
		printf("\n请再次选择运算方式(ESC退出)：\n");
	}
	system("pause");
	return 0;
}

[super_admi]

再加上错误过滤。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>

#define NUMBER_COUNT 2

int main()
{
	int   numbers[NUMBER_COUNT];
	int   i, value, input;
	char  key = '\0';
	char* opt = "+-*/";
	printf("请输入相应数字选择运算方式(ESC退出)：\n1.加法运算\n2.减法运算\n3.乘法运算\n4.除法运算\n");
	while ((key = _getch()) != 0x1b) //0x1b: ESC 
	{
		srand(time(NULL));
		for(i = 0; i < NUMBER_COUNT; i++)
			numbers[i] = rand() % 100 + 1;
		switch (key)
		{
		case '1':
			value = numbers[0] + numbers[1];
			break;
		case '2':
			value = numbers[0] - numbers[1];
			break;
		case '3':
			value = numbers[0] * numbers[1];
			break;
		case '4':
			value = numbers[0] / numbers[1];
			break;
		case 0x1b:
			break;
		default:
			continue;
		}
		printf("\n%d%c%d\n请输入结果：\n", numbers[0],opt[key - '1'],numbers[1]);
		scanf_s("%d",&input);
		printf("%s", value == input ? "你很棒！\n" : "有点遗憾，继续加油！\n");
		printf("\n请再次选择运算方式(ESC退出)：\n");
	}
	system("pause");
	return 0;
}

[super_admi]

应该要考虑清空缓冲区。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>

#define NUMBER_COUNT 2

int main()
{
	int   numbers[NUMBER_COUNT];
	int   i, value, input;
	char  key = '\0';
	char* opt = "+-*/";
	printf("请输入相应数字选择运算方式(ESC退出)：\n1.加法运算\n2.减法运算\n3.乘法运算\n4.除法运算\n");
	while ((key = _getch()) != 0x1b) //0x1b: ESC 
	{
		srand(time(NULL));
		for(i = 0; i < NUMBER_COUNT; i++)
			numbers[i] = rand() % 100 + 1;
		switch (key)
		{
		case '1':
			value = numbers[0] + numbers[1];
			break;
		case '2':
			value = numbers[0] - numbers[1];
			break;
		case '3':
			value = numbers[0] * numbers[1];
			break;
		case '4':
			value = numbers[0] / numbers[1];
			break;
		default:
			continue;
		}
		printf("\n%d%c%d\n请输入结果：\n", numbers[0],opt[key - '1'],numbers[1]);
		scanf_s("%d",&input);
		fflush(stdin);
		printf("%s", value == input ? "你很棒！\n" : "有点遗憾，继续加油！\n");
		printf("\n请再次选择运算方式(ESC退出)：\n");
	}
	system("pause");
	return 0;
}