如何用正则表达式选取指定结果？

aXFD_YY 2018-11-13 01:36:52

比如有一段字符串
06-Nov-2018 14:32:48.678 INFO [localhost-startStop-1] org.apache.catalina.startup.HostConfig.deployDirectory Deployment of web application directory [/root/tomcat/apache-tomcat-8.5.34/webapps/manager] has finished in [103] ms

使用(.*?\s)匹配后结果为
06-Nov-2018
14:32:48.678
INFO
[localhost-startStop-1]
org.apache.catalina.startup.HostConfig.deployDirectory
Deployment
of
web
application
directory
[/root/tomcat/apache-tomcat-8.5.34/webapps/manager]
has
finished
in
[103]

但是只想取前5个结果怎么办？

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十八道胡同 2018-11-13

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package com.demo;



import java.util.ArrayList;

import java.util.List;

import java.util.regex.Matcher;

import java.util.regex.Pattern;



public class Test07 {



    public static void main(String[] args) {



        List<String> result = new ArrayList<String>();



        String REGEX_TIMESCALE = "06-Nov-2018 14:32:48.678 INFO [localhost-startStop-1] org.apache.catalina.startup.HostConfig.deployDirectory Deployment of web application directory [/root/tomcat/apache-tomcat-8.5.34/webapps/manager] has finished in [103] ms";

        Pattern pattern = Pattern.compile("(.*?\\s)");

        Matcher matcher = pattern.matcher(REGEX_TIMESCALE);

        while (matcher.find()) {

            result.add(matcher.group(1));

        }

        System.out.println(result);

    }

}