这是十进制数样板:1001{"userName":"okXU70-dcPj8wBF4-Da4xhhfQXfs","pass":"123456","loginKey":"R2A4PF34"}
服务器端接收客户端传来的字节消息,
注意bytes 是 1001{"userName":"okXU70-dcPj8wBF4-Da4xhhfQXfs","pass":"123456","loginKey":"R2A4PF34"} 的二进制数据
利用 String ss = new String(bytes, "utf-8"); 解析出来的的以下的带乱码的字符串,请问乱码部分如何解析成1001呢?