Python flask框架 虚拟环境中加载环境变量后在网页访问报错,新手提问
报错信息为:
Traceback (most recent call last):
File "/home/python/.local/share/virtualenvs/hellflask-HY3fE-AN/lib/python3.5/site-packages/flask/_compat.py", line 35, in reraise
raise value
File "/home/python/.local/share/virtualenvs/hellflask-HY3fE-AN/lib/python3.5/site-packages/flask/cli.py", line 95, in find_best_app
module=module.__name__
flask.cli.NoAppException: Failed to find Flask application or factory in module "app". Use "FLASK_APP=app:name to specify one.
环境变量为:
FLASK_APP = "app.py"
FLASK_ENV = "development" #开发/生产 环境变量
FLASK_DEBUG = 1 # 制调试模式的开关 1 - 开启 0 - 关闭
FLASK_RUN_HOST = "0.0.0.0"
FLASK_RUN_PORT = "3500"
python版本:3.5
不用加载环境变量:即不安装python-dotenv是可以正常访问的
请各位大佬指教!