python re.findall 模块返回空列表
今天用python爬取前程无忧的招聘信息,最后用正则表达式匹配的时候返回的是空列表,求大佬解答
import re
from urllib import request
def get_content(page):
url="https://search.51job.com/list/000000,000000,0000,00,9,99,%25E5%25A4%25A7%25E6%2595%25B0%25E6%258D%25AE,2,"+str(page)+".html"
rsp=request.urlopen(url)
html=rsp.read()
html=html.decode('gbk')
#print(html)
return html
def get(html):
reg = re.compile(r'class="t1">.*?<a target="_blank" title="(.*?)"href="(.*?)".*?<span class="t2"><a target="_blank" title="(.*?)".*?<span class="t3">(.*?)</span>.*?<span class="t4">(.*?)</span>.*?<span class="t5">(.*?)</span>',re.S) # 匹配换行符
items=re.findall(reg,html)
print(items)
return items