python里，怎么合并相同的数组的值？

[qq_35143564]

例如x=[['北京', 2], ['北京', 1], ['天津', 1], ['福建', 1]]
因为有两个值是北京，所以最后这个数组（也可以是新的数组）应该是：
[['北京', 2，1], ['天津', 1], ['福建', 1]]

[陈年椰子]

简单思路就是整到字典里再转成列表。

x=[['北京', 2], ['北京', 1], ['天津', 1], ['福建', 1]]
x_dict = {}
for xi in x:
    if x_dict.has_key(xi[0]):
        x_temp = x_dict[xi[0]]
        x_temp.append(xi[1])
        x_dict[xi[0]] = x_temp
    else:
        x_dict[xi[0]] = [xi[1]]

x_list = []
for i in  x_dict:
    x_item = [i]
    x_item.extend(x_dict[i])
    x_list.append(x_item)

print(x_list)

[baicaisq]

x = [['北京', 2], ['北京', 1], ['天津', 1], ['福建', 1]]
dict_x = {}

list_x = []
for i in x:
    if i[0] in dict_x.keys():
        dict_x[i[0]].append(i[1])
    else:
        dict_x[i[0]] = [i[0],i[1]]
print(dict_x)
for j in dict_x.keys():
    list_x.append(dict_x[j])
print(list_x)

[galaxybamboo1]

l=[['北京', 2], ['北京', 1], ['天津', 1], ['福建', 1], ['北京', 1]]
dic = dict(l)
tmp_dict = {}
for key in dic:
    tmp_dict[key] =[]
for a,b in l:
    tmp_dict[a].append(b)

lst = []
for k,v in tmp_dict.items():
    tmp_list = [k]
    tmp_list.extend(v)
    lst.append(tmp_list)

print(lst)

[notback]

3楼正解，直接转set,再转回来。

[Mr.Zheng~_]

lists = [1,1,2,3,5,6] # 转为集合（集合可以去重）~_ sets = set(lists) # 再转回数组~_ listss = list(sets) print(listss)

[胖子吴]

dic = {}
l=[['北京', 2], ['北京', 1], ['天津', 1], ['福建', 1], ['北京', 1]]

def func_map(item):
    key = item[0]
    val = item[1]
    if key in dic:
        dic[key] = str(dic[key]) + "," +str(val)
    else:
        dic[key] = val

print([list(i) for i in zip(dic.keys(),dic.values())])

[野狐论禅]

def amp_merge_value(): # 对相同频率的键值对应的波幅进行归一叠加 x_dict = {} for xi in fraq_amplitude: if x_dict.__contains__(xi[0]): x_dict[xi[0]][0] += xi[1] else: x_dict[xi[0]] = [xi[1]] x_list = [] for i in x_dict: x_item = [i] x_item.extend(x_dict[i]) x_list.append(x_item) return x_list

[黄哥Python培训]

方法之一： 先按照地名sort，再遍历一次，即可。 请看代码

[黄哥Python培训]

方法之二： 用字典