想做一个javaWeb的串口工具，实现“打开串口“和“发送指令“功能

[JonesZon]

RT，现在手里有 java客户端的 串口工具代码，但是copy成servlet 后台代码，总是报错，我该如何学习，改进呢？
HTTP Status 500 -
type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

javax.servlet.ServletException: Servlet execution threw an exception
root cause

java.lang.NoClassDefFoundError: gnu/io/UnsupportedCommOperationException
aa.one.LoginServlet.doGet(LoginServlet.java:35)
javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
root cause

java.lang.ClassNotFoundException: gnu.io.UnsupportedCommOperationException
org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1516)
org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1361)
aa.one.LoginServlet.doGet(LoginServlet.java:35)
javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
note The full stack trace of the root cause is available in the Apache Tomcat/6.0.26 logs.

[JonesZon]

public void open() { String commName = "COM1"; String bpsStr = "9600"; int bps = Integer.parseInt(bpsStr); try { // 获得指定端口名及波特率的串口对象 serialPort = Tool.openPort(commName, bps); // 工具 Tool.addListener(serialPort, new SerialListener()); if (serialPort == null) return; } catch (UnsupportedCommOperationException | PortInUseException | NoSuchPortException | TooManyListenersException e1) { e1.printStackTrace(); } }

[JonesZon]

其实很简单，只要配置好rxtxcomm和相应的dll，将java代码进行适当改写，运用get方法（或其他方式）获取前台数据，进行调用读写（servlet 中转到 后台java）即可实现。相应改写，最终实现JavaWeb版本的串口调试工具。