2个JSON对象合并问题~

[even0220]

求教怎么将columnDefs1 和columnDefs2合并变成columnDefs3

谢谢~

    var columnDefs1 = [
                    { headerName: "AirBookingItemId", field: "AirBookingItemId", hide: true },
                    { headerName: "AirBookingHeadId", field: "AirBookingHeadId", hide: true },
                    { headerName: "S.Marks", field: "ShippingMarks", width: 120 },
					{ headerName: "Item SEQ", field: "ItemSequence", width: 130 }
					];
					
    var columnDefs2 = [
                     {
                         field: "ShippingMarks",
                         cellEditor: 'agLargeTextCellEditor',
                         editable: true,
                         width: 120,
                         cellEditorParams: {
                             maxLength: 2000,
                             rows: 15,
                             cols: 61
                         }
                     }
					 ];	
					 
    var columnDefs3 = [
					{ headerName: "AirBookingItemId", field: "AirBookingItemId", hide: true },
                    { headerName: "AirBookingHeadId", field: "AirBookingHeadId", hide: true },
                     {
						 headerName: "S.Marks",
                         field: "ShippingMarks",
						 width: 120,
                         cellEditor: 'agLargeTextCellEditor',
                         editable: true,
                         cellEditorParams: {
                             maxLength: 2000,
                             rows: 15,
                             cols: 61
                         }
                     },
					 { headerName: "Item SEQ", field: "ItemSequence", width: 130 }
					 ];						 

					 

[風灬雲]

假设 columnDefs1和 columnDefs2数据有出入时以 columnDefs1为主，并且每个元素以field作为唯一标记

columnDefs2.forEach(e=>{
let isExist=false;//表示columnDefs2中的这个元素在columnDefs1中不存在
for(let i=0;i<columnDefs1.length;i++){
   if(e.field===columnDefs1[i].field){//如果相同表示存在
      isExist=true;
      for(let key in e){
         columnDefs1[i][key]=columnDefs1[i][key]?columnDefs1[i][key]:e[key]
      };
      break;
   }
}
if(!isExist){//如果不存在，这把元素push到columnDefs1
columnDefs1.push(e)
}
})
console.log(columnDefs1)

[追热]

var columnDefs1 = [
    { headerName: "AirBookingItemId", field: "AirBookingItemId", hide: true },
    { headerName: "AirBookingHeadId", field: "AirBookingHeadId", hide: true },
    { headerName: "S.Marks", field: "ShippingMarks", width: 120 },
    { headerName: "Item SEQ", field: "ItemSequence", width: 130 }
];
var columnDefs2 = [
    {
        field: "ShippingMarks",
        cellEditor: "agLargeTextCellEditor",
        editable: true,
        width: 120,
        cellEditorParams: {
            maxLength: 2000,
            rows: 15,
            cols: 61
        }
    }
]
var columnDefs3 =[];
function ConnectJson(arr1, arr2,arr3) {
    for(var i in arr1){
        arr3.push({});
        for(var j in arr2){
            if(arr1[i].hasOwnProperty('field')&&arr2[j].hasOwnProperty('field')){
                if(arr1[i].field===arr2[j].field){
                  Object.assign(arr3[i],arr1[i],arr2[j]);
                }else {
                    Object.assign(arr3[i],arr1[i]);
                }
            } 
        }
    }
}
ConnectJson(columnDefs1,columnDefs2,columnDefs3);

合并对象用Object.assign方法。

[Hello World,]

用jQuery的extend方法就简单：

var options = $.extend({}, defaults, options);

参考

[Hello World,]

[追热]

引用 4 楼 Hello World, 的回复:

headerName没有了。

[Hello World,]

加一个深拷贝选项：

var cc=$.extend(true,columnDefs1,columnDefs2);