有没有大佬能帮我这个俄罗斯方块的程序加个暂停啊

Nightwalker_ 2019-03-08 02:08:20

我这个俄罗斯方块写出来想加个暂停，但是现在按除了上下左右都是暂停，怎么加一个空格暂停呢？
#include <stdio.h>
#include<windows.h>
#include <conio.h>
#include<time.h>

using namespace std;

//地图数组
int map[250];
//I型方块
int blockI[4] = { 1,1,1,1 };
//T型方块
int blockT[9] = { 0,0,0,1,1,1,0,1,0 };
//L型方块
int blockL[9] = { 0,1,0,0,1,0,0,1,1 };
//O型方块
int blockO[9] = { 0,0,0,0,1,1,0,1,1 };
//S型方块
int blockS[9] = { 0,0,0,0,1,1,1,1,0 };
//Z型方块
int blockZ[9] = { 0,0,0,1,1,0,0,1,1 };
//J型方块
int blockJ[9] = { 0,1,0,0,1,0,1,1,0 };
//下一个方块
int nextblock[2];
//游戏结束标志 1为游戏进行中，0为游戏失败
int endgame;
//记录行进中方块形状和位置,xblock[0]记录形状，0为I型，1为其他型,2为O型
int xblock[2];
//计分
int score;
//初始化数据
void init();
//将光标移动到指定位置
void gotoxy(int x, int y);
//绘制边框
void drawborder();
//绘制地图
void drawmap();
//方块生成
int ranblock();
//绘制方块
void drawblock(int block[9]);
//绘制下一个方块
void drawnextblock(int x);
//向地图上绘制方块
void drawmapblock(int block[9]);
//方块下落
void downblock();
//核心逻辑
void run();

//初始化数据
void init()
{
//map数组初始化赋值，0-239赋值为0，240-249赋值为2
for (int i = 0; i < 240; i++)
map[i] = 0;
for (int i = 240; i < 250; i++)
map[i] = 2;
endgame = 1;
nextblock[0] = 0;
nextblock[1] = ranblock();
xblock[0] = 0;
xblock[1] = 4;
score = 0;
drawborder();

}
//将光标移动到指定位置
void gotoxy(int x, int y)
{
COORD c;
c.X = x + 23;
c.Y = y + 2;
HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
SetConsoleCursorPosition(handle, c);
CONSOLE_CURSOR_INFO CursorInfo;
//获取控制台光标信息
GetConsoleCursorInfo(handle, &CursorInfo);
//隐藏控制台光标,设置控制台光标状态
CursorInfo.bVisible = false;
SetConsoleCursorInfo(handle, &CursorInfo);
}
//绘制边框
void drawborder()
{
//绘制地图边框
for (int i = -1; i < 21; i++)
{
gotoxy(i, -1);
printf("-");
gotoxy(i, 20);
printf("-");
if (i < 19) {
gotoxy(-2, i + 1);
//全角竖线
printf("丨");
gotoxy(20, i + 1);
printf("丨");
}
}
//绘制预览方块边框
for (int i = 0; i < 10; i++)
{
gotoxy(i + 30, 1);
printf("-");
gotoxy(i + 30, 6);
printf("-");
if (i < 4)
{
gotoxy(29, i + 2);
printf("丨");
gotoxy(39, i + 2);
printf("丨");
}
}
gotoxy(30, 8);
printf("下一个方块");
gotoxy(25, 19);
printf("制作者：武伟");
}
//绘制地图
void drawmap()
{
gotoxy(25, 14);
printf(" ");
gotoxy(25, 14);
printf("游戏得分为:%d", score);
for (int i = 40; i < 240; i++)
{
gotoxy(i % 10 * 2, i / 10 - 4);
//map数组中0为空
if (map[i] == 0)
printf(" ");
//1为移动中方块
if (map[i] == 1)
printf("口");
//2为停止的方块
if (map[i] == 2)
printf("口");
}
}

//随机方块生成
int ranblock() {
int x;
srand((int)time(0));
x = rand() % 7;
return x;
}
//绘制方块(除了I型的其他方块)
void drawblock(int block[9]) {
for (int i = 0; i < 3; i++)
{
gotoxy(i * 2 + 31, 3);
if (block[i] == 0)
printf(" ");
else
printf("口");
gotoxy(i * 2 + 31, 4);
if (block[i + 3] == 0)
printf(" ");
else
printf("口");
gotoxy(i * 2 + 31, 5);
if (block[i + 6] == 0)
printf(" ");
else
printf("口");
}
}
//绘制下一个方块
void drawnextblock(int x)
{
for (int i = 0; i < 4; i++)
{
gotoxy(i * 2 + 31, 2);
printf(" ");
gotoxy(i * 2 + 31, 3);
printf(" ");
gotoxy(i * 2 + 31, 4);
printf(" ");
gotoxy(i * 2 + 31, 5);
printf(" ");
}
switch (x)
{
case 0:
gotoxy(31, 4);
printf("口");
gotoxy(33, 4);
printf("口");
gotoxy(35, 4);
printf("口");
gotoxy(37, 4);
printf("口");
break;
case 1:
drawblock(blockT);
break;
case 2:
drawblock(blockL);
break;
case 3:
drawblock(blockO);
break;
case 4:
drawblock(blockS);
break;
case 5:
drawblock(blockZ);
break;
case 6:
drawblock(blockJ);
break;
}
}

//向地图上绘制方块
void drawmapblock(int block[9])
{
for (int i = 0; i < 3; i++)
{
map[i + 13] = block[i];
map[i + 23] = block[i + 3];
map[i + 33] = block[i + 6];
}
//记录方块坐标和类型
xblock[0] = 1;
xblock[1] = 24;
}
//方块下落
void downblock()
{
//碰撞检测标识
int touch = 1;
for (int i = 239; i >= 0; i--)
{
if (map[i] == 1 && map[i + 10] == 2)
touch = 0;
}
if (touch == 1)
{
for (int i = 239; i >= 0; i--)
{
if (map[i] == 1)
{
map[i + 10] = map[i];
map[i] = 0;
}
}
xblock[1] = xblock[1] + 10;
}
else if (touch == 0)
{
for (int i = 0; i < 240; i++)
{
if (map[i] == 1)
map[i] = 2;
}
}
}

//核心逻辑
void run()
{
while (endgame)
{
//游戏结束
for (int i = 20; i < 30; i++)
{
if (map[i] == 2 || map[i + 10] == 2)
{
gotoxy(8, 6);
printf(" ");
gotoxy(8, 7);
printf(" ");
gotoxy(8, 8);
printf(" ");
gotoxy(8, 7);
printf(" 游戏结束，按任意键退出 ");
_getch();
endgame = 0;
}
}
//方块消除
for (int i = 0; i < 24; i++)
{
int sign = 0;
for (int j = 0; j < 10; j++)
{
if (map[i * 10 + j] == 2)
sign++;
}
if (sign == 10)
{
for (int j = 0; j < 10; j++)
{
map[i * 10 + j] = 0;
}
for (int z = i * 10 + 9; z >= 0; z--)
{
if (map[z] == 2)
{
map[z + 10] = 2;
map[z] = 0;
}
}
score++;
drawmap();
}
}
//新方块生成标识
int newblock = 1;
for (int i = 0; i < 240; i++)
{
if (map[i] == 1)
newblock = 0;
}
//生成新方块
if (newblock == 1)
{
switch (nextblock[0])
{
case 0:
map[23] = 1;
map[24] = 1;
map[25] = 1;
map[26] = 1;
xblock[0] = 0;
xblock[1] = 24;
break;
case 1:
drawmapblock(blockT);
break;
case 2:
drawmapblock(blockL);
break;
case 3:
drawmapblock(blockO);
xblock[0] = 2;
break;
case 4:
drawmapblock(blockS);
break;
case 5:
drawmapblock(blockZ);
break;
case 6:
drawmapblock(blockJ);
break;
}
nextblock[0] = nextblock[1];
drawnextblock(nextblock[0]);
nextblock[1] = ranblock();

}
else if (newblock == 0)
{
//方向控制，形态变换
int t = 20000, t1 = 0;
while (t > 0)
{
int ch;
if (t1 < 10 && _kbhit())
{
//需要调用两次，因为功能键第一次返回0或224
ch = _getch();
ch = _getch();
//按下左键，判断左边是否有已经下落的方块和是否已到达左边界，如果没有将正在下落的方块左移
if (ch == 75)
{

for (int i = 0; i < 24; i++)
{
if (map[i * 10] == 1)
ch = 0;
}
if (ch != 0 && xblock[0] == 0 && map[xblock[1] + 1] == 1)
{
if (map[xblock[1] - 2] == 2)
ch = 0;
}
if (ch != 0 && xblock[0] == 0 && map[xblock[1] - 10] == 1)
{
if (map[xblock[1] - 1] == 2)
ch = 0;
}
if (ch != 0 && xblock[0] != 0)
{
for (int i = xblock[1] - 11; i < xblock[1] - 8; i++)
{
if ((map[i] == 1 && map[i - 1] == 2) || (map[i + 10] == 1 && map[i + 9] == 2) || (map[i + 20] == 1 && map[i + 19] == 2))
ch = 0;
}
}
if (ch != 0)
{
for (int i = 0; i < 240; i++)
{
if (map[i] == 1)
{
map[i - 1] = map[i];
map[i] = 0;
}
}
xblock[1] = xblock[1] - 1;
drawmap();
}

}
//按下上按键，判断形态变换后是否重叠已经停止的方块，如没有形态变换
if (ch == 72)
{

for (int i = 0; i < 24; i++)
{
if (i * 10 == xblock[1] || (i * 10 + 9) == xblock[1])
ch = 0;
}

if (ch != 0 && xblock[0] == 0 && map[xblock[1] + 1] == 1 && map[xblock[1] + 10] != 2 && map[xblock[1] - 10] != 2 && map[xblock[1] - 20] != 2)
{
map[xblock[1] + 1] = 0;
map[xblock[1] + 2] = 0;
map[xblock[1] - 1] = 0;
map[xblock[1] + 10] = 1;
map[xblock[1] - 10] = 1;
map[xblock[1] - 20] = 1;
ch = 0;
}
if (ch != 0 && xblock[0] == 0 && map[xblock[1] - 10] == 1 && map[xblock[1] + 1] != 2 && map[xblock[1] + 2] != 2 && map[xblock[1] - 1] != 2)
{
map[xblock[1] + 1] = 1;
map[xblock[1] + 2] = 1;
map[xblock[1] - 1] = 1;
map[xblock[1] + 10] = 0;
map[xblock[1] - 10] = 0;
map[xblock[1] - 20] = 0;
}
if (xblock[0] == 2)
ch = 0;
int tempblock[3][3];
if (ch != 0 && xblock[0] == 1)
{
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
if (map[xblock[1] - 11 + j + i * 10] != 2)
tempblock[i][j] = map[xblock[1] - 11 + j + i * 10];
else
tempblock[i][j] = 0;
}
}
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
if (tempblock[j][2 - i] == 1 && map[xblock[1] - 11 + j + i * 10] == 2)
ch = 0;
}
}
}
if (ch != 0 && xblock[0] == 1)
{
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
if (map[xblock[1] - 11 + j + i * 10] != 2)
map[xblock[1] - 11 + j + i * 10] = tempblock[j][2 - i];
}
}
}
drawmap();
t1 = t1 + 1;
}
//按下右键，判断右边是否有已经下落的方块和是否已到达右边界，如果没有将正在下落的方块右移
if (ch == 77)
{
for (int i = 0; i < 24; i++)
{
if (map[i * 10 + 9] == 1)
ch = 0;

}
if (ch != 0 && xblock[0] == 0 && map[xblock[1] + 1] == 1)
{
if (map[xblock[1] + 3] == 2)
ch = 0;
}
if (ch != 0 && xblock[0] == 0 && map[xblock[1] - 10] == 1)
{
if (map[xblock[1] + 1] == 2)
ch = 0;
}
if (ch != 0 && xblock[0] != 0)
{
for (int i = xblock[1] - 11; i < xblock[1] - 8; i++)
{
if ((map[i] == 1 && map[i + 1] == 2) || (map[i + 10] == 1 && map[i + 11] == 2) || (map[i + 20] == 1 && map[i + 21] == 2))
ch = 0;
}
}
if (ch != 0)
{
for (int i = 239; i >= 0; i--)
{
if (map[i] == 1)
{
map[i + 1] = map[i];
map[i] = 0;
}
}
xblock[1] = xblock[1] + 1;

}
drawmap();
}
//按下按键，方块下落
if (ch == 80)
{
downblock();
drawmap();
break;
}
}
t = t - 1;
}
//自动下落
if (t <= 0)
{
downblock();
drawmap();
}

}
}
}

//入口函数
int main()
{
init();
run();
return 0;
}

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