HttpClient请求POST提示302，直接使用curl可以返回json，怎么修改HttpClient

[对梦想的牵挂]

HttpClient请求POST提示302，而且返回的response中的Localtion是我访问时使用的URL，
例如：我使用的URL是https://bbs.csdn.net?client_id=10333&user=test，
localtion中也是这个https://bbs.csdn.net?client_id=10333&user=test

我试了直接使用curl可以返回json
我的post方法：

public static StringBuilder post(String url, Object data, String encoding) {
		log.info("HttpClient post start => "+url);
		CloseableHttpResponse response = null;
		HttpPost httpPost = null;
		HttpHost httpHost = null;
		StringBuilder responseEntity = null;
		String strings = "";
	
			URL _url = new URL(url);
			
			httpPost = new HttpPost(url);
			
			httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded");

			if(!Stringer.isNullOrEmpty(data)){
				
				log.debug("HttpClient post url => "+url+", data:"+JSON.toJSONString(data));
				
				if (data instanceof Map) {
					// Map方式传参处理
					Map<String,String> params = (Map<String,String>) data;
	
					List<NameValuePair> nvps = new ArrayList<NameValuePair>();
					if (!Stringer.isNullOrEmpty(data)) {
						Set<String> keySet = params.keySet();
						for (String key : keySet) {
							nvps.add(new BasicNameValuePair(key, params.get(key)));
						}
					}
					httpPost.setEntity(new UrlEncodedFormEntity(nvps, encoding));
					
				} else if(data instanceof String){
					// String方式传参处理
					strings = (String)data;
					strings = Stringer.nullToEmpty(strings);
					ByteArrayEntity reqEntity = new ByteArrayEntity(strings.getBytes(encoding));
					reqEntity.setContentEncoding(encoding);
					httpPost.setEntity(reqEntity);
				}
			}
			
			httpPost.setConfig(defaultRequestConfig);
			
			httpHost = new HttpHost(_url.getHost(),_url.getPort());  
			response = httpClient.execute(httpHost,httpPost);
			
			if(!Stringer.isNullOrEmpty(response)){
				log.info("2--HttpClient response  => "+response);
				log.info("3--HttpClient StatusCode  => "+response.getStatusLine().getStatusCode());
				/*if (response.getStatusLine().getStatusCode() != 200) {
	                return null;
	            }*/
				String locationUrl=response.getLastHeader("location").getValue();
				log.info("HttpClient locationUrl  => "+locationUrl);
				log.info("4--HttpClient StatusCode  => "+response.getStatusLine().getStatusCode());

				if (response.getStatusLine().getStatusCode() == 302) {
					Header header = response.getFirstHeader("location"); // 跳转的目标地址是在 HTTP-HEAD上
					String newuri = header.getValue(); // 这就是跳转后的地址，再向这个地址发出新申请
					System.out.println(newuri);

					httpPost = new HttpPost(newuri);
					httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded");


					response = httpClient.execute(httpHost,httpPost);
					int code = response.getStatusLine().getStatusCode();
					locationUrl=response.getLastHeader("location").getValue();
					log.info("5--HttpClient new Code  => "+code);
					log.info("6--HttpClient locationUrl  => "+locationUrl);
				}
				responseEntity = new StringBuilder();
				responseEntity.append(EntityUtils.toString(response.getEntity(), encoding));
				return responseEntity;
			}
			
		return null;
	}

curl命令样例：

curl -k -d "client_id=10333&user=test" "https://bbs.csdn.net"

大神们帮忙看看吧

[tianfang]

302是跳转，自己判断一下是否是302，然后再次打开页面即可 https://blog.csdn.net/bwgang/article/details/8576021

[对梦想的牵挂]

引用 1 楼 tianfang 的回复:

302是跳转，自己判断一下是否是302，然后再次打开页面即可

https://blog.csdn.net/bwgang/article/details/8576021

我试了再次请求，可是给我返回的重定向地址和之前我请求的地址是一样的，再次请求也同样是302。。。。无限月读了

[tianfang]

你的demo url 有get方式传递参数，是不是这个引起的

[tianfang]

从http头Location 中读取跳转url，打开跳转url

[对梦想的牵挂]

引用 3 楼 tianfang 的回复:

从http头Location 中读取跳转url，打开跳转url

这个试过，location中的url和我请求的地址一样，还是302

[对梦想的牵挂]

试过了。不是url的问题

[对梦想的牵挂]

找到原因了，未指定https协议。修改为httpHost = new HttpHost(_url.getHost(),_url.getPort(),“https”); 就可以了