重新补充下
dim src="DEFGH"
label1.text=src
dim TpsCol()=split(src,"")
for i=0 to 100
dim Sort1=sub(tpscol)
dim newScol() as new string(tpscol.length-1)
for i=1 to tpscol.length-1
newscol(i-1)=tpscol(i)
next
newscol(tpscol.length-1)=tpscol(0)
tpscol=newscol
me.begininvoke(sub()
dim lab=new label
lab.text=join(tpscol,"")
me.controls.add(lab)
end sub)
end sub
next
dim src="DEFGH"
label1.text=src
dim TpsCol()=split(src,"")
for i=0 to 100
dim Sort1=sub(tpscol)
dim newScol() as new string(tpscol.length-1)
for i=1 to tpscol.length-1
newscol(i-1)=tpscol(i)
next
newscol(0)=tpscol(tpscol.length-1)
tpscol=newscol
label1.text=join(tpscol,"")
end sub
next
这样不管多少字母都可以循环显示,代码未测试,应该没错