js新手数组问题

[饺子da]

arr = ["123","456","789"];
brr = [["123","a"],["123","b"],["123","c"],["456","d"],["456","e"],["456","f"]];


现在假设我不知道arr和brr里有啥，我想判断brr[i][0]位包不包含arr[i].如果arr的三个元素都包含在brr[i][0]alert("1"),如果有不包含在brr[i][0 ]中的arr元素alert("不包含的元素") 想了好久 做不出 求码.

[天际的海浪]

arr = ["123","456","789"];
brr = [["123","a"],["123","b"],["123","c"],["456","d"],["456","e"],["456","f"]];

crr = [];
brr.forEach(function(v){
	if (arr.indexOf(v[0])==-1)
		crr.push(v[0]);
});
if (crr.length==0) {
	alert(1);
} else {
	alert(crr);
}

[饺子da]

引用 1 楼 天际的海浪 的回复:

arr = ["123","456","789"];
brr = [["123","a"],["123","b"],["123","c"],["456","d"],["456","e"],["456","f"]];

crr = [];
brr.forEach(function(v){
	if (arr.indexOf(v[0])==-1)
		crr.push(v[0]);
});
if (crr.length==0) {
	alert(1);
} else {
	alert(crr);
}

你的结果不对 打印的是1 不是789

[天际的海浪]

arr = ["123","456","789"];
brr = [["123","a"],["123","b"],["123","c"],["456","d"],["456","e"],["456","f"]];

brr.forEach(function(v){
	var n = arr.indexOf(v[0])
	if (n!=-1)
		arr.splice(n,1);
});
if (arr.length==0) {
	alert(1);
} else {
	alert(arr);
}