Linux 中最重要的软件开发工具是 GCC。...利用 gcc 命令可同时编译并连接 C 和 C++ 源程序。 GCC 可同时用来编译 C 程序和 C++ 程序。一般来说,C 编译器通过源文件的后缀名来判断是 C 程序还是 C++ 程序。在 Linux 中
Biorhythms Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 107569 Accepted: 33365 Description ...Some people believe that there are three cycles in a...
C++源代码: // Exponentiation// 2017.03.13 by wyj (COPY)#include using namespace std;// 计算 多 乘以 一 的情况,例如,1234 * 4// many: 多位数// one: 单位数// offset: 乘10偏移// return: 返回计算结果...
//600K 0MS G++ #include #include #include #include using namespace std; ...struct classcomp { bool operator() (const char* lhs, const char* rhs) const { // if (lhs[0] == rhs[0] && lh
题目描述 地图显示,法阵是方形的,纵横皆为五里,在地图上简示为5*5的矩阵,且只由0或1组成。其中,0表示可以走的路,1表示阻止通行的屏障。左上角和右下角分别是阵的入口和出口,这两个位置的数字保证为0。...
这道题目是我现在遇到的最简单的一题,(忽略1000),问题没有任何难度,就是寻找...另外,提交后发现其他孩子的源代码,用C写的,很简洁,他们拿到这个数直接判断,和我们这个方法思路不太一样,当做一种启发吧。http:/
https://vjudge.net/problem/POJ-1401 2.问题描述 For example, they defined the function Z. For any positive integer N, Z(N) is the number of zeros at the end of the decimal form of number N!. The...
题目链接: ...题目大意:平面内最多26个点,给出一些点与点之间的是否相连,问最少使用多少颜色才能给这些点染色,并保证相邻点之间不同色。根据图的四色定理,最多四种颜色就能满足题意。分析:其实用不着用dfs的,用两...
POj 1001源代码——高精度乘单精度POj 1001源代码——高精度乘单精度POj 1001源代码——高精度乘单精度POj 1001源代码——高精度乘单精度
题意:字符的全排列(顺序:'A'<'a'<'B'&...源代码如下: #include<iostream> #include<algorithm> using namespace std; const int MAX =...
Maya Calendar Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 62297 Accepted: 19221 Description During his last sabbatical, professor M. A....
acm新手刷题攻略之poj ac的源码在这找 源码 每做一题,就会把题目画上横杠,并附加解题思路和代码。(近期内先刷codeforces的,准备...(poj3299,poj2159,poj2739,poj1083,poj2262,poj1503,poj3006,poj2255,poj309...
题目大意:以各点为源,比较每次Dijkstra算法求出的值,求出最小值。如果图不连通,输出 Disjoint。 #include using namespace std; #define MAX 1 int n; bool vis[101]; int dis[101][101]; int d[101]; //表示...
题意:给出N个递增的数ai,M个递减的数bi.求是否存在一对ai,bj使得ai+bj=10000. 分析:N<=50000,N^2效率一定不行了.... 设置一个指针i指向a,j指向b. 初始i=1,j=1. ...10000,那么肯定bj+ai'(i'>i)都不等于10000,因为ai...
Red and Black Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 27797 Accepted: 15093 ...There is a rectangular room, covered with square tiles....
POJ_1503: Integer Inquiry Time Limit: 1000 MS Memory Limit: 10 MB 64bit IO Format: %I64d Submitted: 8 Accepted: 3 [Submit][Status][Web Board] Description One of the first users of BIT’s new superc...
Hangover Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 95164 Accepted: 46128 Description ...How far can you make a stack of cards overhang a tabl...
迷宫问题 Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 9325 Accepted: 5523 Description 定义一个二维数组: int maze[5][5] = { ... 0
Exponentiation Time Limit: 500MS Memory Limit: 10000K Total Submissions: 126980 Accepted: 30980 Description ...Problems involving the computation of exact value...
【北大ACM – POJ试题分类】 转载请注明出处:http://exp-blog.com ------------------------------------------------------------------------- 大致题意: 给定一个N*M的地图,地图上有若干个man和house...
POJ 1089 Intervals
这道题目不难,但是有很多细节是需要注意的 1.读入一个带有空格的字符串string,可以采用string类中的getline方法 2.这道题目理解起来有些问题,这里做一些解释:理解题目出了问题 走了很多弯路!...
POJ 3434 Terrarium:题目解答源码 A zoology research lab has a terrarium with rare species of snakes.Terrarium is a flat box filled with soil,and has a glass top allowing to watch the snakes.There...
Radar Installation Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 76845 Accepted: 17213 ...Assume the coasting is an infinite straight line....
Gone Fishing Time Limit: 2000MS Memory Limit: 32768K Total Submissions: 17253 Accepted: 4810 Description John is going on a fishing trip. He has h hours available (1 ), and there are n lakes in ...
Building a Space Stationdescription:You are a member of the space station engineering team, and are assigned a task in the construction process of the station. You are expected to write a computer ...
初期: 一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. ... (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996) 二.图算法: (1)图
NULL 博文链接:https://128kj.iteye.com/blog/1750462
C++源代码: // DNA Sorting // 2017.03.16 by wyj #include #include #include using namespace std; int main() { int n, m, i, j, k, ans[100]; string str[100]; scanf_s("%d%d", &n, &m)...
DNA Sorting Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 77786 Accepted: 31201 Description ...One measure of ``unsortedness'' in a sequence is the...