新手求解多线程信号灯同步的问题，求大神解决

[鱼秋刀]

package CoTest;

/**
 * 信号灯
 * 借助标志位
 * @author yuche
 *
 */

public class CoTest2 {
	public static void main(String[] args) {
		Bread1 bread=new Bread1();
		new Producer1(bread).start();
		new Consumer1(bread).start();

	}

}

class Consumer1 extends Thread{
	Bread1 bread;
	
	public Consumer1(Bread1 bread) {
		super();
		this.bread = bread;
	}

	@Override
	public void run() {
		for(int i=1;i<100;++i) {
			consume();	
		}
	}
	
	public synchronized void consume(){
			if(bread.flag) {
				try {
					this.wait();
				} catch (InterruptedException e) {
					e.printStackTrace();
				}
			}
					System.out.println("消费");
					bread.flag=!bread.flag;
					this.notifyAll();
	}
	
}

class Producer1 extends Thread{
	Bread1 bread;
	
	public Producer1(Bread1 bread) {
		super();
		this.bread = bread;
	}

	@Override
	public void run() {
		for(int i=1;i<100;++i) {
			produce();
		}
}
	
	public synchronized void produce(){
			if(!bread.flag) {
				try {
					this.wait();
				} catch (InterruptedException e) {
					e.printStackTrace();
				}
			}
					System.out.println("生产");
					bread.flag=!bread.flag;
					this.notifyAll();
	}
}

//资源
class Bread1{
	//为T表示面包在生产，为F表示可以消费了
	boolean flag;
	public Bread1() {
		flag=true;
	}
}
	

资源为Bread1，run里面有循环，编译运行就出一次结果，后面的就不运行了

[鱼秋刀]

求大神帮帮忙

[顾工讲码]

你是要写生产者和消费者？

[qq_39936465]

引用 楼主 YuChengwei_ 的回复:

资源为Bread1，run里面有循环，编译运行就出一次结果，后面的就不运行了

你加的锁在2个线程中，没有交点不会相互唤醒。请把，同步方法放入Bread类中

public class CoTest2 {
	public static void main(String[] args) {
		Bread1 bread = new Bread1();
		new Producer1(bread).start();
		new Consumer1(bread).start();

	}

}

class Consumer1 extends Thread {
	Bread1 bread;

	public Consumer1(Bread1 bread) {
		super();
		this.bread = bread;
	}

	@Override
	public void run() {
		for (int i = 1; i < 100; ++i) {
			bread.consume();
		}
	}

	

}

class Producer1 extends Thread {
	Bread1 bread;

	public Producer1(Bread1 bread) {
		super();
		this.bread = bread;
	}

	@Override
	public void run() {
		for (int i = 1; i < 100; ++i) {
			bread.produce();
		}
	}

	
}

//资源
class Bread1 {
	// 为T表示面包在生产，为F表示可以消费了
	boolean flag;

	public Bread1() {
		flag = true;
	}
	public synchronized void consume() {
		if (flag) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		System.out.println("消费");
		flag = !flag;
		this.notifyAll();
	}
	public synchronized void produce() {
		if (!flag) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		System.out.println("生产");
		flag = !flag;
		this.notifyAll();
	}
}

[鱼秋刀]

引用 3 楼 qq_39936465 的回复:

[quote=引用 楼主 YuChengwei_ 的回复:] 资源为Bread1，run里面有循环，编译运行就出一次结果，后面的就不运行了

你加的锁在2个线程中，没有交点不会相互唤醒。请把，同步方法放入Bread类中

public class CoTest2 {
	public static void main(String[] args) {
		Bread1 bread = new Bread1();
		new Producer1(bread).start();
		new Consumer1(bread).start();

	}

}

class Consumer1 extends Thread {
	Bread1 bread;

	public Consumer1(Bread1 bread) {
		super();
		this.bread = bread;
	}

	@Override
	public void run() {
		for (int i = 1; i < 100; ++i) {
			bread.consume();
		}
	}

	

}

class Producer1 extends Thread {
	Bread1 bread;

	public Producer1(Bread1 bread) {
		super();
		this.bread = bread;
	}

	@Override
	public void run() {
		for (int i = 1; i < 100; ++i) {
			bread.produce();
		}
	}

	
}

//资源
class Bread1 {
	// 为T表示面包在生产，为F表示可以消费了
	boolean flag;

	public Bread1() {
		flag = true;
	}
	public synchronized void consume() {
		if (flag) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		System.out.println("消费");
		flag = !flag;
		this.notifyAll();
	}
	public synchronized void produce() {
		if (!flag) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		System.out.println("生产");
		flag = !flag;
		this.notifyAll();
	}
}

[/quote]明白了，感谢大神