scheduling_allocation_algorithm下载

weixin_39821260 2019-08-14 04:00:21

function [Cond_chan,timelong]=Chanbase
global detaT Tnum subNum Chanat
%信道状况矩阵
Psub=2; %自有信道数量
Cond_chan=[];
% timelong=[(Tnum+1000)*ones(Psub,1);10*detaT+(100-10)*detaT*rand(subNum-Psub,1)]; %0-2500的随机数，表示信道的可用/非可用时长
timelong=[(Tnum+1000)*ones(Psub,1);detaT*random('norm',Chanat,5,[subNum-Psub
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function [Cond_chan,timelong]=Chanbase global detaT Tnum subNum Chanat %信道状况矩阵 Psub=2; %自有信道数量 Cond_chan=[]; % timelong=[(Tnum+1000)*ones(Psub,1);10*detaT+(100-10)*detaT*rand(subNum-Psub,1)]; %0-2500的随机数，表示信道的可用/非可用时长 timelong=[(Tnum+1000)*ones(Psub,1);detaT*random('norm',Chanat,5,[subNum-Psub,1])]; %0-2500的随机数，表示信道的可用/非可用时长 for t=detaT:detaT:Tnum chan=zeros(subNum,1); if t>=2*detaT %两个时隙后再进行信道转移 timelong=[timelong,timelong(:,t/detaT-1)-detaT]; %状态变化 for i=1:subNum if timelong(i,t/detaT)<=0 %若时间已到，则更新时长并转移状态 % timelong(i,t/detaT)=10*detaT+(100-10)*detaT*rand(1); %更新时长信息 timelong(i,t/detaT)=detaT*random('norm',Chanat,5,[1,1]); %更新时长信息 chan(i)=abs(Cond_chan(i,t/detaT-1)-1); %转移信道状态，0-1 或1-0 else chan(i)=Cond_chan(i,t/detaT-1); %时间未到，则保持原状态 end end else chan=[ones(Psub,1);round(rand(subNum-Psub,1)+0.2)]; end Cond_chan=[Cond_chan,chan]; end

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