请教"12\34\56\"，如何一次性替换所有"\"符号？

2019-08-19 09:17:59 184 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

CTFshow web入门 web29-------web56 命令执行wp 过滤了flag，可见是文件名过滤，需要查看flag.php 或者flag.txt等文件。此外读取文件利用cat函数，输出利用system、passthru。3.双引号绕过 fl''ag''.php。2.反斜杠绕过 fl\ag.php。1.通配符绕过 fla?还有特殊变量$1、内联执行等。阅读详情

如何能将"12\34\56\"，一次性替换为123456

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一文彻底看懂十进制IP\主机IP\网络IP的三个IP字节转换本文操作的使用软件是VS2010。采用语言是C语言。 1.字节存储顺序多字节数据的各字节在微机中的存放顺序有小端(Little Endian)和大端(Big Endian)之分。Intel体系芯片使用小端，IBM的Power PC使用大端。例如，将0x12345678写入到1000h开始的内存中，结果如图。地址小端方式大端... 阅读详情

StarDnaFox

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切换为时间正序

赵4老师 2019-08-19

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C++ String Literals A string literal consists of zero or more characters from the source character set surrounded by double quotation marks ("). A string literal represents a sequence of characters that, taken together, form a null-terminated string. Syntax string-literal : "s-char-sequenceopt" L"s-char-sequenceopt" s-char-sequence : s-char s-char-sequence s-char s-char : any member of the source character set except the double quotation mark ("), backslash (\), or newline character escape-sequence C++ strings have these types: Array of char[n], where n is the length of the string (in characters) plus 1 for the terminating '\0' that marks the end of the string Array of wchar_t, for wide-character strings The result of modifying a string constant is undefined. For example: char *szStr = "1234"; szStr[2] = 'A'; // Results undefined Microsoft Specific In some cases, identical string literals can be “pooled” to save space in the executable file. In string-literal pooling, the compiler causes all references to a particular string literal to point to the same location in memory, instead of having each reference point to a separate instance of the string literal. The/Gf compiler option enables string pooling. END Microsoft Specific When specifying string literals, adjacent strings are concatenated. Therefore, this declaration: char szStr[] = "12" "34"; is identical to this declaration: char szStr[] = "1234"; This concatenation of adjacent strings makes it easy to specify long strings across multiple lines: cout << "Four score and seven years " "ago, our forefathers brought forth " "upon this continent a new nation."; In the preceding example, the entire string Four score and seven years ago, our forefathers brought forth upon this continent a new nation. is spliced together. This string can also be specified using line splicing as follows: cout << "Four score and seven years \ ago, our forefathers brought forth \ upon this continent a new nation."; After all adjacent strings in the constant have been concatenated, the NULL character, '\0', is appended to provide an end-of-string marker for C string-handling functions. When the first string contains an escape character, string concatenation can yield surprising results. Consider the following two declarations: char szStr1[] = "\01" "23"; char szStr2[] = "\0123"; Although it is natural to assume that szStr1 and szStr2 contain the same values, the values they actually contain are shown in Figure 1.1. Figure 1.1 Escapes and String Concatenation Microsoft Specific The maximum length of a string literal is approximately 2,048 bytes. This limit applies to strings of type char[] and wchar_t[]. If a string literal consists of parts enclosed in double quotation marks, the preprocessor concatenates the parts into a single string, and for each line concatenated, it adds an extra byte to the total number of bytes. For example, suppose a string consists of 40 lines with 50 characters per line (2,000 characters), and one line with 7 characters, and each line is surrounded by double quotation marks. This adds up to 2,007 bytes plus one byte for the terminating null character, for a total of 2,008 bytes. On concatenation, an extra character is added to the total number of bytes for each of the first 40 lines. This makes a total of 2,048 bytes. (The extra characters are not actually written to the string.) Note, however, that if line continuations (\) are used instead of double quotation marks, the preprocessor does not add an extra character for each line. END Microsoft Specific Determine the size of string objects by counting the number of characters and adding 1 for the terminating '\0' or 2 for type wchar_t. Because the double quotation mark (") encloses strings, use the escape sequence (\") to represent enclosed double quotation marks. The single quotation mark (') can be represented without an escape sequence. The backslash character (\) is a line-continuation character when placed at the end of a line. If you want a backslash character to appear within a string, you must type two backslashes (\\). (SeePhases of Translation in the Preprocessor Reference for more information about line continuation.) To specify a string of type wide-character (wchar_t[]), precede the opening double quotation mark with the character L. For example: wchar_t wszStr[] = L"1a1g"; All normal escape codes listed in Character Constants are valid in string constants. For example: cout << "First line\nSecond line"; cout << "Error! Take corrective action\a"; Because the escape code terminates at the first character that is not a hexadecimal digit, specification of string constants with embedded hexadecimal escape codes can cause unexpected results. The following example is intended to create a string literal containing ASCII 5, followed by the characters five: \x05five" The actual result is a hexadecimal 5F, which is the ASCII code for an underscore, followed by the characters ive. The following example produces the desired results: "\005five" // Use octal constant. "\x05" "five" // Use string splicing.

弓人水 2019-08-19

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应该不是转义，否则最后也不是\结尾了。



#include <string>

#include <iostream>

using namespace std;

void removeAll(string &str,char c)

{

    string::iterator new_end = remove_if(str.begin(), str.end(), bind2nd(equal_to<char>(),c));

    str.erase(new_end, str.end());

}

int main()

{

    string tmp="12\\34\\56\\";

    cout<< tmp <<endl;

    removeAll(tmp,'\\');

    cout<< tmp <<endl;

    return 0;

}

636f6c696e 2019-08-19

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转义不好搞吧，如果是char数组另说

羽野子 2019-08-19

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#include<string> #include <iostream> int main() { std::string str("\\12\\56\\"); std::cout << str.c_str() << std::endl;/*\12\56\*/ for (int itr = 0;itr<str.size();++itr) { if (str.at(itr) == '\\') str.replace(itr, 1, ""); } std::cout << str.c_str() << std::endl;/*1256*/ }

StarDnaFox 2019-08-19

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引用 4 楼羽野子的回复:

#include<string>
用std::string 会有意料不到的惊喜

老师能否说具体一点？非常感谢！

羽野子 2019-08-19

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#include<string> 用std::string 会有意料不到的惊喜

请教"12\34\56\"，如何一次性替换所有"\"符号？

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