C# 用multipart/form-data 提交图片，对方接收不到

我是隔壁老刘啊 2019-09-06 08:44:18

我用ASP.NET 模仿用户登录后提交图片，登录这一块已经完成了，可是提交图片的时候总数返回资料导入失败。

下面图片是我在页面正常提交图片的信息

下面是我模仿时候提交的信息

下面是代码



 #region 将文件转成二进制

            byte[] fileContentByte = new byte[1024]; // 文件内容二进制

            string filePath = "图片路径..确保能拿到";

            FileStream fs = new FileStream(filePath, FileMode.Open, FileAccess.Read);

            fileContentByte = new byte[fs.Length]; // 二进制文件

            fs.Read(fileContentByte, 0, Convert.ToInt32(fs.Length));

            fs.Close();



            #endregion

            string imgname = "商户协议1";

            #region 定义请求体中的内容 并转成二进制

            string boundary = "WebKisf2242undary3JNFl4OsfUY7123B";

            string Enter = "\r\n";



            string docId ="------" + boundary + Enter

                 + "Content-Disposition: form-data; name=\"docId\"" + Enter + Enter

                 + ""; //感觉就是这个值有问题，当值是 "" 的时候返回 资料导入失败，

                         //当这个值是  " " 的时候返回资料已经存在，

                        //只要这个值不是    ""   ，都返回资料已经存在，



            string docTypes = Enter + "------" + boundary + Enter

                  + "Content-Disposition: form-data; name=\"docType\"" + Enter + Enter

                  + "" + docType + "";



            string docChildTypes =Enter+ "------" + boundary + Enter

                    + "Content-Disposition: form-data: name=\"docChildType\"" + Enter + Enter

                    + "" + docChildType + "";            



            string fileContentStr = Enter + "------" + boundary + Enter

                    + "Content-Disposition: form-data; name=\"file\"; filename=\"" + imgname + "\"" + Enter

                    + "Content-Type: image/jpeg" + Enter + Enter ;



            string merInIds = Enter + "------" + boundary + Enter

                     + "Content-Disposition: form-data; name=\"merInId\"" + Enter + Enter

                     + "" + merInId + "";



            string weib = Enter + "------" + boundary + "--" + Enter;





            var docChildTypesStrByte = Encoding.UTF8.GetBytes(docChildTypes);

            var docIdStrByte = Encoding.UTF8.GetBytes(docId);

            var docTypeStrByte = Encoding.UTF8.GetBytes(docTypes);

            var merInIdsStrByte = Encoding.UTF8.GetBytes(merInIds);

            var fileContentStrByte = Encoding.UTF8.GetBytes(fileContentStr);

            var weibStrByte = Encoding.UTF8.GetBytes(weib);



            #endregion





            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);

            request.Method = "POST";

            request.ContentType = "multipart/form-data;boundary=----" + boundary;

            request.KeepAlive = true;

            request.CookieContainer = ZhCook(url, cookmain);



            Stream myRequestStream = request.GetRequestStream();//定义请求流



            #region 将各个二进制 安顺序写入请求流 modelIdStr -> (fileContentStr + fileContent) -> uodateTimeStr -> encryptStr



            myRequestStream.Write(docIdStrByte, 0, docIdStrByte.Length);

            myRequestStream.Write(docTypeStrByte, 0, docTypeStrByte.Length);

            myRequestStream.Write(docChildTypesStrByte, 0, docChildTypesStrByte.Length);                 

            myRequestStream.Write(fileContentStrByte, 0, fileContentStrByte.Length);

            myRequestStream.Write(fileContentByte, 0, fileContentByte.Length);

            myRequestStream.Write(merInIdsStrByte, 0, merInIdsStrByte.Length);

            myRequestStream.Write(weibStrByte, 0, weibStrByte.Length);

            #endregion



            HttpWebResponse response = (HttpWebResponse)request.GetResponse();//发送



            Stream myResponseStream = response.GetResponseStream();//获取返回值

            StreamReader myStreamReader = new StreamReader(myResponseStream, Encoding.GetEncoding("utf-8"));



            string retString = myStreamReader.ReadToEnd();



            myStreamReader.Close();

            myResponseStream.Close();