QT中静态函数无法直接用emit发出信号,那请问有什么方法可以发一个信号呢?

[weixin_38056491]

rt...那个static函数,无法改造成普通函数,需要在里面发出一个信号,但是如果这样,emit又无法使用,那要如何发出一个信号呢?

[weixin_38088709]

引用第5楼kinzess于2010-02-19 08:07发表的  :ls2位的方法貌似都不错~~谢谢了`~我试试~~ 弄出来没的，我也遇到了这个问题；你是怎么处理的?

[weixin_38073387]

ls2位的方法貌似都不错~~谢谢了`~我试试~~

[weixin_38068392]

Use this static function to change a static variable. emit your signal just after this static func call according to the change of this static variable.引用第2楼kinzess于2010-02-17 12:50发表的  :那静态函数我就是没办法更改,所以才如此头痛......

[weixin_38066087]

postevent然后在事件处理里面emit

[weixin_38061328]

引用第1楼steinlee于2010-02-17 01:14发表的  :inside a static function you can call only static functions. Emitting a signal is not a static function call.Therefore, it will not work. You need to work around this. You can change this func to be nonstatic.那静态函数我就是没办法更改,所以才如此头痛......

[Iceblood_kaka]

inside a static function you can call only static functions. Emitting a signal is not a static function call.Therefore, it will not work. You need to work around this. You can change this func to be nonstatic.

[weixin_38095754]

楼主，您好，这种方法在qt4.8.2里 貌似行不通额？