PAT 树的同构问题(新人求解)

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为什么我的程序编译执行没问题，但是建了一棵树之后程序就弹出了呢？ 源程序如下 #include<stdlib.h> #include<string.h> #include<stdio.h> #define MaxTree 10 #define Null -1 typedef int Tree; typedef char ElementType; struct TreeNode { ElementType element; Tree left; Tree right; }T1[MaxTree],T2[MaxTree]; Tree BuildTree( struct TreeNode T[] ); Tree Isomorphic(Tree R1,Tree R2); int main() { Tree R1,R2; R1=BuildTree(T1); R2=BuildTree(T2); if(Isomorphic(R1,R2)) printf("yes\n"); else printf("no\n"); return 0; } BuildTree( struct TreeNode T[] ) { int check[10]; int N,Root; char cl,cr; scanf("%d\n",&N); if(N){ for(int i=0;i<N;i++) check[i]=0; for(int m=0;m<N;m++) { scanf("%c%c%c\n",&T[m].element,&cl,&cr); if(cl!='-') { T[m].left=cl-'0'; check[T[m].left]=1; } else T[m].left=Null; if(cr!='-') { T[m].right=cr-'0'; check[T[m].right]=1; } else T[m].right=Null; } for(int n=0;n<N;n++) { if(check==0) break; } Root=n;} return Root; } Tree Isomorphic(Tree R1,Tree R2) { struct TreeNode T[MaxTree]; if((R1==Null)&&(R2==Null)) return 1; if(((R1!=Null)&&(R2==Null))||((R1==Null)&&(R2!=Null))) return 0; if(T[R1].element!=T[R2].element) return 0; if((T[R1].left==Null)&&(T[R2].left==Null)) return Isomorphic(T[R1].right,T[R2].right); if(((T[R1].left!=Null)&&(T[R2].left!=Null))&&((T[T[R1].left].element)==(T[T[R2].left].element))) return (Isomorphic(T[R1].left,T[R2].left)&&Isomorphic(T[R1].right,T[R2].right)); else return (Isomorphic(T[R1].left,T[R2].right)&&Isomorphic(T[R1].right,T[R2].left)); }