初学C++的小菜鸟，(统计字符串中各个数字出现的个数)感觉没问题啊，为什么统计输出是全零？？？

[m0_45673538]

#include<iostream> using namespace std; int main() { int i,j; int n=0; int m[10]={0}; char s[50]; cin>>s; for(i=0;i<50;i++) if(s[i]>='0'&&s[i]<='9') { n++; j=s[i]; m[j]=m[j]+1; } cout<<"Number's amount is:"<<n<<endl; cout<<"'0...9'amount is:"; for(i=0;i<10;i++) cout<<m[i]<<" "; return 0; }

[智者知已应修善业]

j = (s[i]-'0');

[智者知已应修善业]

	int i=0, j=0;
	int n = 0;
	int m[10] = { 0 };
	char s[50];
	cin >> s; 
	for (i = 0; i<50; i++)
		if (s[i] >= '0'&&s[i] <= '9')
		{
			n++; cout << (j=s[i])<<"\t"<<(s[i]-'0')<<endl;
			j = (s[i]-'0');
			m[j] = m[j] + 1;
		}
	cout << "Number's amount is:" << n << endl;
	cout << "'0...9'amount is:";
	for (i = 0; i<10; i++)
		cout << m[i] << " ";

[laoxu9824]

#include "stdafx.h"; #include <iostream>; using namespace std; int count_str() { int i, j; int n = 0; int m[10] = { 0 }; char s[50]; cin >> s; cout << "input: " << s << "\n"; for (i = 0; i<strlen(s); i++) if (s[i] >= '0'&&s[i] <= '9') { n++; j = s[i] - '0'; m[j] = m[j] + 1; } else { cout << "Invalid char at pos: " << i << ", with value, " << s[i] << "\n"; }; cout << "Number's amount is:" << n << endl; cout << "'0...9'amount is:"; for (i = 0; i<10; i++) cout << m[i] << " "; return 0; }

[laoxu9824]

[智者知已应修善业]

教你一招制胜

[datoulaile123]

自己打好断点一步步调试看数据的变化，然后看看是哪步代码没有按照自己设定的走再进行修改，直接拿别人给你写好的代码永远不会进步，光标定位的那行按F9可打断点和取消断点

[智者知已应修善业]

打断点有时觉得麻烦,那就把写好才打印屏幕随意复制到任何想要查看的地方,觉得还是比较方便.