建立个split函数，然后行转列，然后按列排序
CREATE FUNCTION [dbo].[SplitStr]
(
@string nvarchar(max),
@symbol nvarchar(10)
)
RETURNS @table TABLE(id int identity,value nvarchar(max))
AS
begin
DECLARE @splitlen int
SET @splitlen=LEN(@symbol)-1
WHILE CHARINDEX(@symbol,@string)>0
BEGIN
INSERT @table(value) VALUES(LEFT(@string,CHARINDEX(@symbol,@string)-1))
SET @string=STUFF(@string,1,CHARINDEX(@symbol,@string)+@splitlen,'')
END
INSERT @table(value) VALUES(@string)
return
end
declare @tb table(ver nvarchar(20))
insert into @tb values('1.0.0.5'),('1.0.0.6'),('1.0.0.8'),('1.0.0.9'),('1.0.0.10'),('1.0.0.12')
select *
from @tb
cross apply (
select convert(int,[1]) as v1,convert(int,[2]) as v2,convert(int,[3]) as v3,convert(int,[4]) as v4
from (
select * from master.dbo.splitStr(ver,'.')
) a
pivot(max(value) for id in ([1],[2],[3],[4])) p
) b
order by v1 desc,v2 desc,v3 desc,v4 desc
(6 行受影响)
ver v1 v2 v3 v4
-------------------- ----------- ----------- ----------- -----------
1.0.0.12 1 0 0 12
1.0.0.10 1 0 0 10
1.0.0.9 1 0 0 9
1.0.0.8 1 0 0 8
1.0.0.6 1 0 0 6
1.0.0.5 1 0 0 5
(6 行受影响)
