Dom4j解析复杂xml获取想要的内容

一只开发狗001 2019-12-12 09:51:05

先上xml如下



<?xml version="1.0" encoding="utf-8"?>

<feed xml:base="" xmlns=""  xmlns:d="" xmlns:m="">

    <id></id>

    <title type="text">Users</title>

    <updated>2019-12-11T02:28:30Z</updated>

    <link rel="self" title="Users" href="Users"/>

    <entry>

        <id>(1L)</id>

        <category term="" scheme=""/>

        <link rel="edit" title="User" href="Users(1L)"/>

        <link rel=""    type="application/atom+xml;type=feed" title="Sessions" href="Users(1L)/Sessions"/>

        <title/>

        <updated>2019-12-11T02:28:30Z</updated>

        <author>

            <name/>

        </author>

        <content type="application/xml">

            <m:properties>

                <d:Id m:type="Edm.Int64">1</d:Id>

                <d:Sid>S-1-5-7</d:Sid>

                <d:Upn></d:Upn>

                <d:UserName>ANONYMOUS LOGON</d:UserName>

                <d:FullName></d:FullName>

                <d:Domain></d:Domain>

                <d:CreatedDate m:type="Edm.DateTime">2019-11-20T05:01:43.2</d:CreatedDate>

                <d:ModifiedDate m:type="Edm.DateTime">2019-11-20T05:01:43.2</d:ModifiedDate>

            </m:properties>

        </content>

    </entry>

    <entry>

        <id></id>

        <category term=""   scheme=""/>

        <link rel="edit" title="User" href="Users(2L)"/>

        <link rel=""   type="application/atom+xml;type=feed" title="Sessions" href="Users(2L)/Sessions"/>

        <title/>

        <updated>2019-12-11T02:28:30Z</updated>

        <author>

            <name/>

        </author>

        <content type="application/xml">

            <m:properties>

                <d:Id m:type="Edm.Int64">2</d:Id>

                <d:Sid>S-1-5-21-916077177-3160758025-4246751474-1106</d:Sid>

                <d:Upn>text01@text.com</d:Upn>

                <d:UserName>text01</d:UserName>

                <d:FullName>textt01</d:FullName>

                <d:Domain>LINGHANG</d:Domain>

                <d:CreatedDate m:type="Edm.DateTime">2019-11-21T05:49:47.823</d:CreatedDate>

                <d:ModifiedDate m:type="Edm.DateTime">2019-12-02T04:55:24.29</d:ModifiedDate>

            </m:properties>

        </content>

    </entry>

</feed>

xml中有多个entry节点需要遍历，遍历后如何得到其子节点中d:的属性值，遍历没啥问题，但是遍历后寻找这个节点下的子节点就出了问题，老是显示获取的内容为空，求大神指教，指向获得这些属性值将其变为List<Map>,谢谢

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一只开发狗001 2019-12-12

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问题已经解决

dkwuxiang 2019-12-12

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public static void main(String[] args) throws DocumentException {
		SAXReader reader = new SAXReader();
		List<Map<String, String>> result = new ArrayList<Map<String, String>>();
        File file = new File("C:\\Users\\lenovo\\Desktop\\javaUtils\\111.xml");

        Document document = reader.read(file);

        Element root = document.getRootElement();
        List<Element> entrys = root.elements("entry");
        for (Element entry : entrys) {
        	Element content = entry.element("content");
        	Element m = content.element("properties");
        	List<Element> elements = m.elements();
        	Map<String, String> map = new HashMap<String, String>();
        	for (Element d : elements) {
        		map.put(d.getName(), d.getText());
			}
        	result.add(map);

        }
        System.out.println(result);
	}