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求大神帮忙看看这个要怎么改
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /mofifyUser.jsp at line 6
3: <head> <title>修改用户信息</title></head>
4: <body>
5: <% //读取用户原有信息
6: int id = Integer.parseInt(request.getParameter("id"));
7: UserManage usermanage = new ncu.util.UserManage() ;
8: UserInfo userinfo = usermanage.getUserById(id);
9: usermanage.closeConn();
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:524)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:435)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
ncu.filter.CharsetEncodingFilter.doFilter(CharsetEncodingFilter.java:17)
root cause
java.lang.NumberFormatException: null
java.lang.Integer.parseInt(Integer.java:415)
java.lang.Integer.parseInt(Integer.java:497)
org.apache.jsp.mofifyUser_jsp._jspService(mofifyUser_jsp.java:60)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:393)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
ncu.filter.CharsetEncodingFilter.doFilter(CharsetEncodingFilter.java:17)
note The full stack trace of the root cause is available in the Apache Tomcat/6.0.13 logs.
...全文
三仙半 2020年01月03日
你是不是没有判断ID字段是否输入就提交到服务器了？java.lang.NumberFormatException: null应该是在说，将输入解析为整数时，遇到了输入为null。