mybatis中resultMap无法合并部分数据

景培培哎 2020-02-29 05:43:34
我的数据分为三个表,但是其中一个表的数据用resultMap无法合并起来,想请教各位大神,这应该怎么解决?
代码如下:
mapper:

<resultMap id="GroupOfOrder" type="com.chenjiabao.takeaway.entity.GroupOfOrder">
<id property="id" column="id" jdbcType="INTEGER"/>
<result property="orderId" column="order_id" jdbcType="VARCHAR"/>
<result property="note" column="note" jdbcType="VARCHAR"/>
<result property="openid" column="openid" jdbcType="VARCHAR"/>

<collection property="cartes" ofType="com.chenjiabao.takeaway.entity.SysCarte">
<id column="carte_id" property="id" jdbcType="INTEGER"/>
<result property="dishname" column="carte_dishName" jdbcType="VARCHAR"/>
<result property="price" column="carte_price" jdbcType="NUMERIC"/>
<result property="material" column="carte_Material" jdbcType="VARCHAR"/>
<result property="classification" column="carte_classification" jdbcType="VARCHAR"/>
<result property="specification" column="carte_specification" jdbcType="VARCHAR"/>
<result property="photourl" column="carte_photoUrl" jdbcType="VARCHAR"/>
<result property="carteNum" column="carte_num" jdbcType="VARCHAR"/>
</collection>

<collection property="address" ofType="com.chenjiabao.takeaway.entity.UserAddress">
<id column="address_id" property="id" jdbcType="INTEGER"/>
<result property="name" column="address_name" jdbcType="VARCHAR"/>
<result property="phone" column="address_phone" jdbcType="VARCHAR"/>
<result property="province" column="address_province" jdbcType="VARCHAR"/>
<result property="city" column="address_city" jdbcType="VARCHAR"/>
<result property="area" column="address_Area" jdbcType="VARCHAR"/>
<result property="address" column="address_Address" jdbcType="VARCHAR"/>
<result property="sex" column="address_sex" jdbcType="VARCHAR"/>
</collection>
</resultMap>



<!-- 查询语句 -->
<select id="query" resultMap="GroupOfOrder">
select so.id,
so.order_id,

sc.id as 'carte_id',
sc.dishName as 'carte_dishName',
sc.price as 'carte_price',
sc.Material as 'carte_Material',
sc.classification as 'carte_classification',
sc.specification as 'carte_specification',
sc.photoUrl as 'carte_photoUrl',

ua.id as 'address_id',
ua.name as 'address_name',
ua.phone as 'address_phone',
ua.province as 'address_province',
ua.city as 'address_city',
ua.Area as 'address_Area',
ua.Address as 'address_Address',
ua.sex as 'address_sex',

so.carte_num,
so.note,
so.openid
from sys_order so,
sys_carte sc,
user_address ua
where so.carte_id = sc.id
and so.address_id = ua.id
</select>



GroupOfOrder实体类:

/**
* 地址
*/
private UserAddress address;
/**
* 主键
*/
private Integer id;
/**
* 订单编号
*/
private String orderId;
/**
* 所选菜品及个数
*/
private List<SysCarte> cartes;
/**
* 总价
*/
private Double totalprice;
/**
* 备注
*/
private String note;
/**
* openid
*/
private String openid;

public UserAddress getAddress() {
return address;
}

public void setAddress(UserAddress address) {
this.address = address;
}

public Integer getId() {
return id;
}

public void setId(Integer id) {
this.id = id;
}

public String getOrderId() {
return orderId;
}

public void setOrderId(String orderId) {
this.orderId = orderId;
}

public List<SysCarte> getCartes() {
return cartes;
}

public void setCartes(List<SysCarte> cartes) {
this.cartes = cartes;
}

public Double getTotalprice() {
return totalprice;
}

public void setTotalprice(Double totalprice) {
this.totalprice = totalprice;
}

public String getNote() {
return note;
}

public void setNote(String note) {
this.note = note;
}

public String getOpenid() {
return openid;
}

public void setOpenid(String openid) {
this.openid = openid;
}

@Override
public boolean equals(Object o) {
if (this == o) return true;

if (!(o instanceof GroupOfOrder)) return false;

GroupOfOrder that = (GroupOfOrder) o;

return new EqualsBuilder()
.append(getAddress(), that.getAddress())
.append(getId(), that.getId())
.append(getOrderId(), that.getOrderId())
.append(getCartes(), that.getCartes())
.append(getTotalprice(), that.getTotalprice())
.append(getNote(), that.getNote())
.append(getOpenid(), that.getOpenid())
.isEquals();
}

@Override
public int hashCode() {
return new HashCodeBuilder(17, 37)
.append(getAddress())
.append(getId())
.append(getOrderId())
.append(getCartes())
.append(getTotalprice())
.append(getNote())
.append(getOpenid())
.toHashCode();
}

@Override
public String toString() {
return "GroupOfOrder{" +
"address=" + address +
", id=" + id +
", orderId='" + orderId + '\'' +
", cartes=" + cartes +
", totalprice=" + totalprice +
", note='" + note + '\'' +
", openid='" + openid + '\'' +
'}';
}


(SysCarte)实体类:

public class SysCarte implements Serializable {
private static final long serialVersionUID = -79961121051443787L;
/**
* 主键
*/
private Integer id;
/**
* 菜名
*/
private String dishname;
/**
* 价格
*/
private Double price;
/**
* 所用材料
*/
private String material;
/**
* 菜品分类
*/
private String classification;
/**
* 菜品规格
*/
private String specification;
/**
* 菜品图片
*/
private String photourl;

/**
* 菜品个数
*/
private String carteNum;


public Integer getId() {
return id;
}

public void setId(Integer id) {
this.id = id;
}

public String getDishname() {
return dishname;
}

public void setDishname(String dishname) {
this.dishname = dishname;
}

public Double getPrice() {
return price;
}

public void setPrice(Double price) {
this.price = price;
}

public String getMaterial() {
return material;
}

public void setMaterial(String material) {
this.material = material;
}

public String getClassification() {
return classification;
}

public void setClassification(String classification) {
this.classification = classification;
}

public String getSpecification() {
return specification;
}

public void setSpecification(String specification) {
this.specification = specification;
}

public String getPhotourl() {
return photourl;
}

public void setPhotourl(String photourl) {
this.photourl = photourl;
}

public String getCarteNum() {
return carteNum;
}

public void setCarteNum(String carteNum) {
this.carteNum = carteNum;
}


输出结果:

{
"status": 200,
"msg": "OK",
"data": [
{
"address": {
"id": 1,
"openid": null,
"name": "张晓明",
"phone": "334455",
"province": "北京",
"city": "北京",
"area": "海淀区",
"sex": "男"
},
"id": 1,
"orderId": "df123456",
"cartes": [
{
"id": 1,
"dishname": "银耳粥",
"price": 10.0,
"material": "1",
"classification": "2",
"specification": "3",
"photourl": "4",
"carteNum": "1"
}
],
"totalprice": null,
"note": null,
"openid": "123456"
},
{
"address": {
"id": 2,
"openid": null,
"name": "李云龙",
"phone": "112233",
"province": "北京",
"city": "北京",
"area": "海淀区",
"address": "秀丽王府",
"sex": "女"
},
"id": 2,
"orderId": "df456789",
"cartes": [
{
"id": 2,
"dishname": "辣椒炒肉",
"price": 15.0,
"material": "1",
"classification": "2",
"specification": "3",
"photourl": "4",
"carteNum": "2"
}
],
"totalprice": null,
"note": null,
"openid": "456789"
},
{
"address": {
"id": 2,
"openid": null,
"name": "李云龙",
"phone": "112233",
"province": "北京",
"city": "北京",
"area": "海淀区",
"address": "秀丽王府",
"sex": "女"
},
"id": 3,
"orderId": "df456789",
"cartes": [
{
"id": 1,
"dishname": "银耳粥",
"price": 10.0,
"material": "1",
"classification": "2",
"specification": "3",
"photourl": "4",
"carteNum": "1"
}
],
"totalprice": null,
"note": null,
"openid": "456789"
}
],
"ok": null
}




应该怎样才能吧cartes字段合并起来,求大神支招
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景培培哎 2020-03-02
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引用 5 楼 亦夜 的回复:
[quote=引用 4 楼 景培培哎 的回复:] [quote=引用 1 楼 亦夜 的回复:] 应该是你的结构定义的可能还有些问题吧,我看你的map映射除了address那里应该用对象映射,其他好像没什么问题,我猜你想返回的结构应该是 多个GroupOfOrder对象所以返回类型应该是 List<GroupOfOrder> 而每一个GroupOfOrder里面有自己的属性,以及每一个对应的address对象,同时还有List<Carte>对象 正常的结构应该是这样


 "data": [
    {
      "id": 1,
      "orderId": "df123456",
      "totalprice": null,
      "note": null,
      "openid": "123456",
      "address": {
        "id": 1,
        "openid": null,
        "name": "张晓明",
        "phone": "334455",
         "province": "北京",
        "city": "北京",
        "area": "海淀区",
        "sex": "男"
      },
      "cartes": [
        {
          "id": 1,
          "dishname": "银耳粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        },
         {
          "id": 2,
          "dishname": "小米粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        }
      ]
    }
  ]
我的GroupOfOrde里面有list 有普通数据 也有对象,现在是完全不知道该怎么解决[/quote] 就正常映射啊,属性对应字段,对象用单个的对象映射,list就用collection映射[/quote] 谢谢大佬耐心指点,我已经解决了,谢谢
亦夜 2020-03-01
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应该是你的结构定义的可能还有些问题吧,我看你的map映射除了address那里应该用对象映射,其他好像没什么问题,我猜你想返回的结构应该是 多个GroupOfOrder对象所以返回类型应该是 List<GroupOfOrder> 而每一个GroupOfOrder里面有自己的属性,以及每一个对应的address对象,同时还有List<Carte>对象 正常的结构应该是这样


 "data": [
    {
      "id": 1,
      "orderId": "df123456",
      "totalprice": null,
      "note": null,
      "openid": "123456",
      "address": {
        "id": 1,
        "openid": null,
        "name": "张晓明",
        "phone": "334455",
         "province": "北京",
        "city": "北京",
        "area": "海淀区",
        "sex": "男"
      },
      "cartes": [
        {
          "id": 1,
          "dishname": "银耳粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        },
         {
          "id": 2,
          "dishname": "小米粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        }
      ]
    }
  ]
亦夜 2020-03-01
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引用 4 楼 景培培哎 的回复:
[quote=引用 1 楼 亦夜 的回复:] 应该是你的结构定义的可能还有些问题吧,我看你的map映射除了address那里应该用对象映射,其他好像没什么问题,我猜你想返回的结构应该是 多个GroupOfOrder对象所以返回类型应该是 List<GroupOfOrder> 而每一个GroupOfOrder里面有自己的属性,以及每一个对应的address对象,同时还有List<Carte>对象 正常的结构应该是这样


 "data": [
    {
      "id": 1,
      "orderId": "df123456",
      "totalprice": null,
      "note": null,
      "openid": "123456",
      "address": {
        "id": 1,
        "openid": null,
        "name": "张晓明",
        "phone": "334455",
         "province": "北京",
        "city": "北京",
        "area": "海淀区",
        "sex": "男"
      },
      "cartes": [
        {
          "id": 1,
          "dishname": "银耳粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        },
         {
          "id": 2,
          "dishname": "小米粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        }
      ]
    }
  ]
我的GroupOfOrde里面有list 有普通数据 也有对象,现在是完全不知道该怎么解决[/quote] 就正常映射啊,属性对应字段,对象用单个的对象映射,list就用collection映射
景培培哎 2020-03-01
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引用 1 楼 亦夜 的回复:
应该是你的结构定义的可能还有些问题吧,我看你的map映射除了address那里应该用对象映射,其他好像没什么问题,我猜你想返回的结构应该是 多个GroupOfOrder对象所以返回类型应该是 List<GroupOfOrder> 而每一个GroupOfOrder里面有自己的属性,以及每一个对应的address对象,同时还有List<Carte>对象 正常的结构应该是这样


 "data": [
    {
      "id": 1,
      "orderId": "df123456",
      "totalprice": null,
      "note": null,
      "openid": "123456",
      "address": {
        "id": 1,
        "openid": null,
        "name": "张晓明",
        "phone": "334455",
         "province": "北京",
        "city": "北京",
        "area": "海淀区",
        "sex": "男"
      },
      "cartes": [
        {
          "id": 1,
          "dishname": "银耳粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        },
         {
          "id": 2,
          "dishname": "小米粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        }
      ]
    }
  ]
我的GroupOfOrde里面有list 有普通数据 也有对象,现在是完全不知道该怎么解决
景培培哎 2020-03-01
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引用 1 楼 亦夜 的回复:
应该是你的结构定义的可能还有些问题吧,我看你的map映射除了address那里应该用对象映射,其他好像没什么问题,我猜你想返回的结构应该是 多个GroupOfOrder对象所以返回类型应该是 List<GroupOfOrder> 而每一个GroupOfOrder里面有自己的属性,以及每一个对应的address对象,同时还有List<Carte>对象 正常的结构应该是这样


 "data": [
    {
      "id": 1,
      "orderId": "df123456",
      "totalprice": null,
      "note": null,
      "openid": "123456",
      "address": {
        "id": 1,
        "openid": null,
        "name": "张晓明",
        "phone": "334455",
         "province": "北京",
        "city": "北京",
        "area": "海淀区",
        "sex": "男"
      },
      "cartes": [
        {
          "id": 1,
          "dishname": "银耳粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        },
         {
          "id": 2,
          "dishname": "小米粥",
          "price": 10.0,
          "material": "1",
          "classification": "2",
          "specification": "3",
          "photourl": "4",
          "carteNum": "1"
        }
      ]
    }
  ]
我就是想把cartes合并起来,但是我现在无论怎么修改,都合并不起来,求大神支招

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