请问一个数组中有多个对象，每个对象中又有数组，这种数据怎么遍历出来

[东东Da]

let ps = [  

            {  
                teacherName:'1',  
                students:['111','222']  
            },  
            {  
                teacherName:'2',  
                students:['333','444']  
            },  
            {  
                teacherName:'3',  
                students:['555','666']  
            }  
        ];

[东东Da]

就是后台拿到的数据，我用map方法，遇到里面对象还有数组，不知道如何解决

[天际的海浪]

let ps = [  
            {  
                teacherName:'1',  
                students:['111','222']  
            },  
            {  
                teacherName:'2',  
                students:['333','444']  
            },  
            {  
                teacherName:'3',  
                students:['555','666']  
            }  
        ];
ps.forEach(function(v){
	console.log("teacherName : " ,v.teacherName);
	v.students.forEach(function(x){
		console.log(x);
	});
});

[不开花的玫瑰]

你是要怎么样的遍历呢？楼上的代码可以遍历出所有的数据。 JS有一个find方法，如果你想要获取对应的数据，比如说获取到teacherName等于1的students属性，那你可以尝试一下使用find

[kkjjww]

function sss(p,s){ var kg="------------------------------------------"; for(var i in p){ if((typeof p[i])=="object"){ console.log(kg.substring(0,s*2)+""+i); s++; sss(p[i],s); s--; }else{ console.log(kg.substring(0,s*2)+""+i+"->"+p[i]); } }

[阿拉斯攀登]

2层循环遍历

[淘人居士]

let ps = [  

            {  
                teacherName:'1',  
                students:['111','222']  
            },  
            {  
                teacherName:'2',  
                students:['333','444']  
            },  
            {  
                teacherName:'3',  
                students:['555','666']  
            }  
        ];
//提取数组合并
Array.prototype.concat.apply([],ps.map(d=>d.students));

提取数组合并成一维数组，然后就能简单遍历了