Jquery Mobile+php 提交表单及后台接收跳转问题

IF先生 2020-07-20 04:00:19

刚开始学想JqueryMobile，用JqueryMobile + PHP做个移动端，一开始做登陆页面就遇到表单提交问题，怎样提交都没有反应也不会跳转！
请各位大神解惑！

前端提交表单代码



<body>



    <div data-role="page" id="login">

        <div data-role="header">

            <h1>用戶登入</h1>

        </div>

        <div data-role="content">

            <form id="form1" name="form1" method="post" action="#">

              <div data-role="fieldcontain">

                <input type="text" name="username" id="username" placeholder="用戶名">

                <input type="password" name="password" id="password" placeholder="密碼">

                <input type="submit" data-role="button" id="submit" value="登入" onClick="ajax_login()">

              </div>

            </form>

                <p>沒有帳號？<a href="#register" data-transition="slide">點擊註冊</a></p>

        </div>

		

		<div data-role="footer" style="text-align: center"  data-position="fixed">

        	<p>CopyRight ©2020</p>

    	</div>

    </div>

  

	<script> 

	function ajax_login() {		

		var username = $("#username").val();

		var password = $("#password").val();

		var urlweb = "loading_check.php";	

		

		if (username==""){

			layer.open({content: '請輸入用戶名！',btn: '好的'});

			document.getElementById("username").focus();

			return false;	

		}

		 if (password==""){

			layer.open({content: '請輸入密碼！',btn: '好的'});

			document.getElementById("password").focus();

			return false;	

		}	

		

		$.ajax({

			type: "POST",

			url: urlweb,

			dataType:'json',

	               data: {user:username,pass:password},

			beforeSend: function () {

				document.getElementById("submit").value = "正在登入中";			

			},		

			success: function (json) {

				if(json.Loge==3){

					document.getElementById("submit").value = "登入成功";

					window.self.location='admin/input.html';

				}else if(json.Loge==1){

					layer.open({content: '帳戶名錯誤',skin: 'footer'});

					document.getElementById("txtname").focus();

					document.getElementById("submit").value = "重新登入";

				}

			}

		});

	}	

		

	</script>

	

</body>

后台PHP接收处返回信息



include("conn/conn.php");

$user=$_REQUEST['username'];

$pass=md5($_REQUEST['password']);

$sql = mysql_query("select * from user where Nmber='".$user."' and   Pass='".$pass."' ");

if($result = mysql_fetch_array($sql)){ 



		echo json_encode(array ('Loge'=>3)); 

}else{

		echo json_encode(array ('Loge'=>1)); 



}

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