请教一下lambda表达式的改写

[flyskytoday]

public class lazyMan {

	private lazyMan(){
		System.out.println(Thread.currentThread().getName()+"OK");
	}
	
	private static lazyMan lazyman;
	
	public static lazyMan getInstance(){
		if(lazyman == null){
			lazyman = new lazyMan();
		}
		return lazyman;
	}
	
	public static void main(String[] args) {
		for(int i=0;i<10;i++){
			new Thread(()->{
					lazyMan.getInstance();
			}).start();
		}
	}
}

其中的

			new Thread(()->{
					lazyMan.getInstance();
			}).start();

改成非lambda表达式，怎么修改？

[qq_39936465]

引用 楼主 flyskytoday 的回复:

public class lazyMan {

	private lazyMan(){
		System.out.println(Thread.currentThread().getName()+"OK");
	}
	
	private static lazyMan lazyman;
	
	public static lazyMan getInstance(){
		if(lazyman == null){
			lazyman = new lazyMan();
		}
		return lazyman;
	}
	
	public static void main(String[] args) {
		for(int i=0;i<10;i++){
			new Thread(()->{
					lazyMan.getInstance();
			}).start();
		}
	}
}

其中的

			new Thread(()->{
					lazyMan.getInstance();
			}).start();

改成非lambda表达式，怎么修改？

 new Thread(new Runnable() {
				@Override
				public void run() {
					// TODO Auto-generated method stub
					 lazyMan.getInstance();
				}
			}).start();

[开心就好O]

new Thread() { @Override public void run() { lazyMan.getInstance(); } }.start();

[KeepSayingNo]

public class lazyManThread extends Thread{ @Override public void run() { lazyMan.getInstance(); } } 修改下main方法 lazyManThread thread = new lazyManThread （）； thread.run();

[略知java的景初]

new Thread() { @Override public void run() { lazyMan.getInstance(); } }.start();

[flyskytoday]

引用 2 楼 KeepSayingNo 的回复:

public class lazyManThread extends Thread{ @Override public void run() { lazyMan.getInstance(); } } 修改下main方法 lazyManThread thread = new lazyManThread （）； thread.run();

这上面是jdk1.8代码没问题，但改为1.6还是有问题，线程的lambda还请多指点下

引用 1 楼 开心就好O 的回复:

new Thread() { @Override public void run() { lazyMan.getInstance(); } }.start();

这上面是jdk1.8代码没问题，但改为1.6还是有问题，线程的lambda还请多指点下