python中for循环问题代码

[工具人01]

# 需求：猜测Sun的女朋友的年龄.
# 中间任意一次猜对，游戏通关结束
# 猜错3次，问是否还要继续。
# 如果继续，可继续猜测3次，以此循环；
# 如果停止，则游戏退出；

#!/usr/bin/env python 
# -*- coding:utf-8 -*-
# Author:Bell Sun

age_of_Sun_gf = 25
i = 0
print(type(i))
for i in range(4):

    guess_age_of_Sun_gf = int(input("Please input Bell Sun's girlfriend age:"))
    if age_of_Sun_gf == guess_age_of_Sun_gf:
        print("Your guess is right !")
        break
    elif age_of_Sun_gf <  guess_age_of_Sun_gf:
        print("Your guess is too big !")
    else:
        print("Your guess is too low !")
    print("i =", i)
    while i == 3:
        guess_continue = input("if you want to continue guess , please don't press 'n' .")
        print("this")
        if guess_continue != 'n':
            i = 0
            print("i =", i)
        else:
            print("See you next time !")

[本性之初]

我觉得while在外面来判定游戏是否结束，然后用一个flag判断次数就好

[裸泳摸鱼冠军]

游戏开始 跳入while死循环,. 里面进行游戏, 然后进行判断跳出

[你抱着的是只熊]

可以这样做，如下： age_of_Sun_gf = 25 times = 1 # 用于计数猜测的次数 while True: #先判断当前的计数如果大于3了，就询问是否继续，若输入'n'则结束，其他则继续！ if times > 3: guess_continue = input("if you want to continue guess , please don't press 'n' .") if guess_continue != 'n': times = 1#如果用户想继续猜，就把计数器times重置为1 continue else: break guess_age_of_Sun_gf = int(input("Please input Bell Sun's girlfriend age:")) if age_of_Sun_gf == guess_age_of_Sun_gf: print("Your guess is right !") break elif age_of_Sun_gf < guess_age_of_Sun_gf: print("Your guess is too big !") times += 1#猜测小于女友年龄，则把猜测次数加1 else: print("Your guess is too low !") times += 1##猜测大于女友年龄，则把猜测次数加1

[欢乐的小猪]

我想你应该了解下递归函数

def func(age_of_Sun_gf):
    for i in range(3):
        guess_age_of_Sun_gf = int(input("Please input Bell Sun's girlfriend age:"))
        if age_of_Sun_gf == guess_age_of_Sun_gf :
            print("Your guess is right !")
            break
        elif age_of_Sun_gf < guess_age_of_Sun_gf :
            print("Your guess is too big !")
        else :
            print("Your guess is too low !")
        i += 1
    if i==3:
        guess_continue = input("if you want to continue guess , please don't press 'n' .")
        if guess_continue != 'n' :
            func(age_of_Sun_gf)
        else :
            print("See you next time !")
    else:
        return True

func(25)

[工具人01]

#!/usr/bin/env python 
# -*- coding:utf-8 -*-
# Author:Bell Sun

age_of_Sun_gf = 25
i = 0

while i < 3:
    guess_age_of_Sun_gf = int(input("Please input Bell Sun's girlfriend age:"))
    if age_of_Sun_gf == guess_age_of_Sun_gf:
        print("Your guess is right !")
        break
    elif age_of_Sun_gf <  guess_age_of_Sun_gf:
        print("Your guess is too big !")
    else:
        print("Your guess is too low !")
    print("i =", i)
    i += 1
    if i == 3:
        guess_continue = input("if you want to continue guess , please don't press 'n' .")
        if guess_continue != 'n':
            i = 0
        else:
            print("See you next time !")

外面用while循环是可以实现需求的，但是把外面的替换成for循环就会出现问题，请问有什么合适的方法吗

[丰耳]

因为你犯了一个认知错误，循环外的变量i和for i in range(4)里的i，不是一个i，for循环的i取值来自range(4)，而不是你定义的i=0，这里你即使把i赋值100,在你的for循环中的这个i还是从0开始，这样解释不知道你明白了没，可参见下图：

[丰耳]

你还是没理解for循环的原理，代码中运算改变的“i”值不会影响for i in range(4)里的这个“i”，具体你可以去了解下for循环的原理，这里给你举个例子，你大概能看明白：

[工具人01]

引用 6 楼 丰耳 的回复:

因为你犯了一个认知错误，循环外的变量i和for i in range(4)里的i，不是一个i，for循环的i取值来自range(4)，而不是你定义的i=0，这里你即使把i赋值100,在你的for循环中的这个i还是从0开始，这样解释不知道你明白了没，可参见下图：

明白了，原来是这个意思，那在22中i赋值成了0怎么不生效，这个怎么解