如何用Java实现Elasticsearch脚本排序

[sky我的世界]

如下图所示的查询语句，用Java如何实现呀 我百度了官网也没看到如何实现，我用的是ES6.5.3 跪求

[sky我的世界]

急求大佬解答！！！

[sky我的世界]

解决了 参考： 通过脚本排序 数据内容： "_source": { "userid": 123, "city": [ 102 ], "expection2": [ 2496 ], "sex": 1, "age": 31, "cate_score": [ "580:0.9", "581:0.5", "593:0.2", "706:0.1", "606:0.65" ], "lmodtime": 1459347878, } } 1 2 根据业务方传入的类型数据去cate_score字段里面去找，如果找到对应的类型那么根据返回的类型数据进行排序。比如传入580那么所有的数据按照cate_score中580的数据分值数据去排序 String scriptCode="脚本内容"; System.out.println(scriptCode); Map<String, Object> params = new HashMap<>(); params.put("cate", 606); Script script = new Script(ScriptType.INLINE,"painless",scriptCode,params); SortBuilder sortBuilder = SortBuilders.scriptSort(script, ScriptSortBuilder.ScriptSortType.NUMBER); sortBuilder.order(SortOrder.DESC); SearchSourceBuilder sb = new SearchSourceBuilder(); sb.sort(sortBuilder); System.out.println(sb.toString()); SearchResponse search = client.search(new SearchRequest(new String[] { "supin_index_test" }, sb)); SearchHit[] hits = search.getHits().getHits(); for (SearchHit hit : hits) { System.out.println(hit.getSourceAsMap()); } painless脚本： int size = doc['cate_score.keyword'].length; double score = -0.1; int targetCate = params.cate; for (int i = 0; i < size; i++) { def path = doc['cate_score.keyword'][i]; int flag = path.lastIndexOf(':'); double get_score = Double.parseDouble(path.substring(flag + 1)); int get_cate = Integer.parseInt(path.substring(0, flag)); if (get_cate == targetCate) { score = get_score; break; } } return score