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SELECT
B.Gendar
,COUNT(DISTINCT A.clientID) AS CT
FROM service AS A
JOIN Client AS B ON A.clientID=B.clientID
WHERE A.service='email'
GROUP BY
B.Gendar
CT即是你所求的email服务的男女人数SELECT
B.Gendar
,COUNT(DISTINCT A.clientID) AS CT
FROM service AS A
JOIN Client AS B ON A.clientID=B.clientID
WHERE A.service='email'
GROUP BY
CT即是你所求的男女email服务的人数