正则表达式优化

[wang_jinhai]

增加适应这种公式：＝e8+(d10+......-d25)
其中 d10+......-d25 表示
d10-d11+d12-d13+d14-d15+d16-d17+d18-d19+d20-d21+d22-d23+d24-d25

大神，麻烦帮忙修改一下，无限感谢！

要求：
a1+.....+a4,代表连续相加：a1+a2+a3+a4
c1+...-c4如上面案案例，间隔加减:c1-c2+c3-c4

<table id="tab">
    <tr>
        <td id="a1">70</td>
        <td id="a2">-60</td>
        <td id="a3"></td>
        <td id="a4">10</td>
        <td id="a5">=a1-a2-b5</td>
    </tr>
    <tr>
        <td id="b1">10</td>
        <td id="b2">20</td>
        <td id="b3">60</td>
        <td id="b4">40</td>
        <td id="b5">=a1+(b1+....-b4)</td>
    </tr>
    <tr>
        <td id="c1">20</td>
        <td id="c2">30</td>
        <td id="c3">60</td>
        <td id="c4">=a1+.....+a4</td>
        <td id="c5">=c1+...-c4</td>
    </tr>
</table>
<script type="text/javascript">
function calc(obj) {
    var str = obj.innerText;
    if (/^\s*$/.test(str))
        return 0;
    if (str[0]=="=") {
        obj.innerText = eval(str.slice(1).replace(/([a-z]+)(\d+)([\+\-\*\/])\.{3,}([\+\-\*\/])([a-z]+)(\d+)/ig,function (s,w1,n1,c1,c2,w2,n2) {
            var arr = [];
            n1 = parseInt(n1, 10);
            n2 = parseInt(n2, 10);
            for (var i = n1; i < n2; i++)
                arr.push(w1+i);
            return arr.join(c1)+c2+w2+n2;
        }).replace(/[a-z]+\d+/ig,function (s) {
            return "("+calc(document.getElementById(s))+")";
        }));
    }
    return obj.innerText;
}
 
var td = document.querySelectorAll("#tab td");
for (var i = 0, len = td.length; i < len; i++) {
    calc(td[i]);
}
</script>

[天际的海浪]

<table id="tab">
    <tr>
        <td id="a1">70</td>
        <td id="a2">-60</td>
        <td id="a3"></td>
        <td id="a4">10</td>
        <td id="a5">=a1-a2-b5</td>
    </tr>
    <tr>
        <td id="b1">10</td>
        <td id="b2">20</td>
        <td id="b3">60</td>
        <td id="b4">40</td>
        <td id="b5">=a1+(b1+....-b4)</td>
    </tr>
    <tr>
        <td id="c1">20</td>
        <td id="c2">30</td>
        <td id="c3">60</td>
        <td id="c4">=a1+.....+a4</td>
        <td id="c5">=c1+...-c4</td>
    </tr>
</table>
<script type="text/javascript">
function calc(obj) {
    var str = obj.innerText;
    if (/^\s*$/.test(str))
        return 0;
    if (str[0]=="=") {
        obj.innerText = eval(str.slice(1).replace(/([a-z]+)(\d+)([\+\-\*\/])\.{3,}([\+\-\*\/])([a-z]+)(\d+)/ig,function (s,w1,n1,c1,c2,w2,n2) {
            n1 = parseInt(n1, 10);
            n2 = parseInt(n2, 10);
            var str = w1 + n1;
            for (var i = n1+1; i <= n2; i++)
                str += ((n2-i)%2==0?c2:c1) + w1 + i;
            return str;
        }).replace(/[a-z]+\d+/ig,function (s) {
            return "("+calc(document.getElementById(s))+")";
        }));
    }
    return obj.innerText;
}
 
var td = document.querySelectorAll("#tab td");
for (var i = 0, len = td.length; i < len; i++) {
    calc(td[i]);
}
</script>

[v18664661368]