C# DLL注入后无法执行，求大神帮助。

AngleBlueWing 2020-12-30 02:49:28

近日做期末计算机程序结课设计，题目是C#开发一个DLL并注入到explorer.exe并执行，好不容易贪黑写完了终于能注入了，但是注入后无法自动执行，各种百度也不行，眼看日期临近实在没有办法了，望各路大神出手相助，谢谢！
附C# dll注入源代码（XP下可运行（32位））：

using System;
using System.Collections.Generic;
using System.Text;
using System.Runtime.InteropServices;
using System.Diagnostics;

namespace DllInjectA
{
class Program
{
[DllImport("kernel32.dll")] //声明API函数
public static extern int VirtualAllocEx(IntPtr hwnd, int lpaddress, int size, int type, int tect);

[DllImport("kernel32.dll")]
public static extern int WriteProcessMemory(IntPtr hwnd, int baseaddress, string buffer, int nsize, int filewriten);

[DllImport("kernel32.dll")]
public static extern int GetProcAddress(int hwnd, string lpname);

[DllImport("kernel32.dll")]
public static extern int GetModuleHandleA(string name);

[DllImport("kernel32.dll")]
public static extern int CreateRemoteThread(IntPtr hwnd, int attrib, int size, int address, int par, int flags, int threadid);

static void Main(string[] args)
{
int ok1;
int baseaddress;
int temp = 0;
int hack;
int yan;
string dllname;

dllname = "c:\\test.dll";
int dlllength;
dlllength = dllname.Length + 1;
Process[] pname = Process.GetProcesses(); //取得所有进程

foreach (Process name in pname) //遍历进程
{
//MessageBox.Show(name.ProcessName.ToLower());
if (name.ProcessName.ToLower().IndexOf("svchost") != -1) //所示记事本，那么下面开始注入
{
baseaddress = VirtualAllocEx(name.Handle, 0, dlllength, 4096, 4); //申请内存空间
if (baseaddress == 0) //返回0则操作失败
{
Console.WriteLine("申请内存空间失败！！");
return;
}

ok1 = WriteProcessMemory(name.Handle, baseaddress, dllname, dlllength, temp); //写内存
if (ok1 == 0)
{
Console.WriteLine("写内存失败！！");
return;
}

hack = GetProcAddress(GetModuleHandleA("Kernel32"), "LoadLibraryA"); //取得loadlibarary在kernek32.dll地址

if (hack == 0)
{
Console.WriteLine("无法取得函数的入口点！！");
return;
}

yan = CreateRemoteThread(name.Handle, 0, 0, hack, baseaddress, 0, temp); //创建远程线程

if (yan == 0)
{
Console.WriteLine("创建远程线程失败！！");
return;
}
else
{
Console.WriteLine("已成功注入dll!");
Console.ReadKey();
return;
}
}
}
}
}
}

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