如何获取下级元素的内容

[somebody-998]

<div id="spot">
	<div class="cont"> 
		<ul> 
			<li class="func__size"><p>1</p><div>122x32m</div><div>1256x455p</div></li> 
			<li class="func__size"><p>2</p><div>222x32m</div><div>2256x455p</div></li> 
			<li class="func__size"><p>3</p><div>322x32m</div><div>3256x455p</div></li> 
		</ul> 
	</div> 
	<div class="cont"> 
		<ul> 
			<li class="func__size"><p>1</p><div>122x32m</div><div>1256x455p</div></li> 
			<li class="func__size"><p>2</p><div>222x32m</div><div>2256x455p</div></li> 
			<li class="func__size"><p>3</p><div>322x32m</div><div>3256x455p</div></li>  
		</ul> 
	</div>
</div>
 

我想鼠标点击li的时候，获取li里面的p跟两个div里面的内容，请问能实现么，谢谢

[howcoder]

<script src="https://cdn.bootcss.com/jquery/3.3.1/jquery.min.js"></script> <script type="text/javascript"> $(".func__size").click(function () { console.log($(this).html()); }) </script>

[天际的海浪]

<div id="spot">
	<div class="cont"> 
		<ul> 
			<li class="func__size"><p>1</p><div>122x32m</div><div>1256x455p</div></li> 
			<li class="func__size"><p>2</p><div>222x32m</div><div>2256x455p</div></li> 
			<li class="func__size"><p>3</p><div>322x32m</div><div>3256x455p</div></li> 
		</ul> 
	</div> 
	<div class="cont"> 
		<ul> 
			<li class="func__size"><p>1</p><div>122x32m</div><div>1256x455p</div></li> 
			<li class="func__size"><p>2</p><div>222x32m</div><div>2256x455p</div></li> 
			<li class="func__size"><p>3</p><div>322x32m</div><div>3256x455p</div></li>  
		</ul> 
	</div>
</div>
 
<script type="text/javascript">
Array.from(document.querySelectorAll(".func__size")).forEach(dom=>{
	dom.addEventListener("click", function (e) {
		var p = this.querySelector("p");
		var div = this.querySelectorAll("div");
		alert(p.innerHTML);
		alert(div[0].innerHTML);
		alert(div[1].innerHTML);
	}, false);
});
</script>

[aiweiya520]

$(".func__size").click(function(){ pText = $(this).find("p").text(); firstText = $(this).find("div:nth-child(2)").text(); secondText = $(this).find("div:nth-child(3)").text(); alert("p的内容是"+ pText +";第一个div的内容是"+ firstText +";第二个div的内容是"+ secondText); })

[somebody-998]

谢谢楼上三位回答，十分感谢