新手求教大神：Python如何统计列表中各数值分别为第几次出现

[J莳柒]

例：列表为[2,3,2,1,1,3]
如何实现得出的结果为{2:1,3:1,2:2,1:1,1:2,3:2}

[shoppo0505]

用 Window.partitionBy

[cclxpp123]

lst = [2,3,2,1,1,3]

a = []
b = {}
for x in lst:
    b[x] = b[x]+1 if b.get(x) else 1
    a.append((x, (b[x] if b.get(x) else 1)))
print(a)

[rrrr336]

lst = [2,3,2,1,1,3]
a = [(lst[i], lst[:i+1].count(lst[i])) for i in range(len(lst))]
print(a)
#[(2, 1), (3, 1), (2, 2), (1, 1), (1, 2), (3, 2)]