C++代码转C

[三楼の郎]

#include <iostream>

int main(int argc, char* argv[])
{
    std::cout.setf( std::ios_base::unitbuf ); //instead of "<< eof" and "flushall"
    unsigned int a, c, i, t=0;
    std::string inp;
    bool bCommunicationEnds = false;

    do {

        inp="";
        t=0;
        // Sum the first 4 chars from stdin (the length of the message passed).
        for (i = 0; i <= 3; i++)
        {
//          t += getchar();
            t += std::cin.get();
        }
        // Loop getchar to pull in the message until we reach the total
        //  length provided.
        for (i=0; i < t; i++)
        {
            //c = getchar();
            c = std::cin.get();
            //if(c == EOF)
            if(c == 65)
            {
                bCommunicationEnds = true;
                i = t;
            }
            else
            {
                inp += c;
            }
        }

        if(!bCommunicationEnds)
        {
            //Collect the length of the message
             unsigned int len = inp.length();
            //unsigned int len = strJson.length();
            //// We need to send the 4 btyes of length information
            std::cout << char(((len>>0) & 0xFF))
                << char(((len>>8) & 0xFF))
                << char(((len>>16) & 0xFF))
                << char(((len>>24) & 0xFF));
            //// Now we can output our message
            std::cout << inp;

        }
    }while(!bCommunicationEnds);
    return 0;
}

这个是C++的吧，那位大哥有功夫的帮忙把上面那段代码转成C的，都二十来年没搞过C基本都忘光光了啊，C++是更不行，大体上知道是从输入流转输出的，有闲工夫的帮忙搭把手啊，先谢过了

[赵4老师]

#include <stdio.h>
int main(int argc, char* argv[])
{
    unsigned int a, c, i, t=0;
    char inp[1024];//assume max len is 1024
    int k=0;
    int bCommunicationEnds = 0;
    k=0;
    do {

        inp[k++]=0;
        t=0;
        // Sum the first 4 chars from stdin (the length of the message passed).
        for (i = 0; i <= 3; i++)
        {
            t += getchar();
        }
        // Loop getchar to pull in the message until we reach the total
        //  length provided.
        for (i=0; i < t; i++)
        {
            c = getchar();
            //if(c == EOF)
            if(c == 65)
            {
                bCommunicationEnds = 1;
                i = t;
            }
            else
            {
                inp[k++] = c;
            }
        }

        if(!bCommunicationEnds)
        {
            //Collect the length of the message
             unsigned int len = k;
            //unsigned int len = strJson.length();
            //// We need to send the 4 btyes of length information
            printf("%c%c%c%c",
                   char(((len>>0) & 0xFF)),
                   char(((len>>8) & 0xFF)),
                   char(((len>>16) & 0xFF)),
                   char(((len>>24) & 0xFF)));
            //// Now we can output our message
            for (i=0;i<k;i++) printf("%c",inp[i]);
 
        }
    }while(!bCommunicationEnds);
    return 0;
}

[三楼の郎]

引用 1 楼 赵4老师 的回复:

#include <stdio.h>
int main(int argc, char* argv[])
{
    unsigned int a, c, i, t=0;
    char inp[1024];//assume max len is 1024
    int k=0;
    int bCommunicationEnds = 0;
    k=0;
    do {

        inp[k++]=0;
        t=0;
        // Sum the first 4 chars from stdin (the length of the message passed).
        for (i = 0; i <= 3; i++)
        {
            t += getchar();
        }
        // Loop getchar to pull in the message until we reach the total
        //  length provided.
        for (i=0; i < t; i++)
        {
            c = getchar();
            //if(c == EOF)
            if(c == 65)
            {
                bCommunicationEnds = 1;
                i = t;
            }
            else
            {
                inp[k++] = c;
            }
        }

        if(!bCommunicationEnds)
        {
            //Collect the length of the message
             unsigned int len = k;
            //unsigned int len = strJson.length();
            //// We need to send the 4 btyes of length information
            printf("%c%c%c%c",
                   char(((len>>0) & 0xFF)),
                   char(((len>>8) & 0xFF)),
                   char(((len>>16) & 0xFF)),
                   char(((len>>24) & 0xFF)));
            //// Now we can output our message
            for (i=0;i<k;i++) printf("%c",inp[i]);
 
        }
    }while(!bCommunicationEnds);
    return 0;
}

灰常感谢，昨晚上自己整了一晚上都不行