求助！！！HTTP Status 500 - Request processing failed

[沉梦昂志、]

运行SSM的java程序后，登录后台是出现这样的显示：
HTTP Status 500 - Request processing failed; nested exception is org.springframework.jdbc.BadSqlGrammarException:
exception

org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.jdbc.BadSqlGrammarException:
### Error querying database. Cause: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'admin a where 1=1

and a.username = 'admin'' at line 1
### The error may exist in com/entity/admin.xml
### The error may involve com.dao.AdminDAO.getAdminByCond-Inline
### The error occurred while setting parameters
### SQL: select a.* from admin a where 1=1 and a.username = ?
### Cause: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'admin a where 1=1

and a.username = 'admin'' at line 1
; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'admin a where 1=1

and a.username = 'admin'' at line 1
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:982)
org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:872)
javax.servlet.http.HttpServlet.service(HttpServlet.java:648)
org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:846)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:197)
org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:107)

[getdate]

你的SQL 在 数据库那边能执行成功么? select a.* from admin a where 1=1 and a.username = 'admin'