如何查出某个表的表结构

[aloneone]

如题

[pengdali]

select d.name,a.name ,b.name ,a.length, a.isnullable from syscolumns a, systypes b,sysobjects d where a.xtype=b.xusertype and a.id=d.id and d.xtype='U'

[pengdali]

SELECT
(case when a.colorder=1 then d.name else '' end) N'表名',
a.colorder N'字段序号',
a.name N'字段名',
(case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end) N'标识',
(case when (SELECT count(*)
FROM sysobjects
WHERE (name in
(SELECT name
FROM sysindexes
WHERE (id = a.id) AND (indid in
(SELECT indid
FROM sysindexkeys
WHERE (id = a.id) AND (colid in
(SELECT colid
FROM syscolumns
WHERE (id = a.id) AND (name = a.name))))))) AND
(xtype = 'PK'))>0 then '√' else '' end) N'主键',
b.name N'类型',
a.length N'占用字节数',
COLUMNPROPERTY(a.id,a.name,'PRECISION') as N'长度',
isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0) as N'小数位数',
(case when a.isnullable=1 then '√'else '' end) N'允许空',
isnull(e.text,'') N'默认值',
isnull(g.[value],'') AS N'字段说明'
--into ##tx

FROM syscolumns a left join systypes b
on a.xtype=b.xusertype
inner join sysobjects d
on a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join syscomments e
on a.cdefault=e.id
left join sysproperties g
on a.id=g.id AND a.colid = g.smallid
order by object_name(a.id),a.colorder

[txlicenhe]

我一般用这个视图
Create view fielddesc
as
select o.name as oname, c.name as cname,convert(varchar(30),p.value) as value,p.smallid as psmallid,t.name as tname
from syscolumns c
join systypes t on c.xtype = t.xtype
join sysobjects o on o.id=c.id
left join sysproperties p on p.smallid=c.colid and p.id=o.id
where o.xtype='U'

查询时:
Select * from fielddesc where oname = '你的表名'

[cloudchen]

简单的
sp_help 表名

[aloneone]

好极了，我先试一下。

[hjb111]

sp_columns 表名